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Thanx alot!! ....ii)
f(x) = g(x)
2x - a = x^2 - 6x
x^2 - 8x + a = 0
Since one real solution, D = 0
D = b^2 - 4ac = 0
(-8)^2 - 4(1)(a) = 0
64 - 4a = 0
a = 16
iv)
let y = x^2 - 6x
y = x^2 - 6x + (-3)^2 - (-3)^2
y = (x - 3)^2 - 9
(x - 3)^2 = y + 9
x - 3 = √(y + 9)
x = √(y + 9) + 3
h-1(x) = √(x + 9) + 3
Domain: x ≥ -9
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_1.pdf
Hi guys..How to do number 11 i)?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_1.pdf
Hi guys..How to do number 11 i)?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_13.pdf
Hey guys. need help in question 8 part i) and ii). I think they got the answer wrong in the MS and ER for part i because it's only differentiated once and it's supposed to be differentiated twice.
part 4 (ii)
Loss occurs when X<0.Can someone please help me with 2(ii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_62.pdf
Thank you!!Loss occurs when X<0.
P(X<0) = P(Z < 0 - 6.4/5.2)
= P(Z < - 1.231)
= 1 - Φ(1.231)
= 1 - 0.8909
= 0.1091
This is the probability of loss on any random given day.
Now finding the probability that loss occurs on exactly 1 of the next 4 days:
n = 4
r = 1
p = 0.1091
q = 0.8909
Probability = [4C1] (0.1091) (0.8909)³ = 0.309
thank youin first one
after finding a put it in the equation and find its derivative,put the derivative as 0 so that u find the stationary values of x,now do double derivative and put these values of x and see if points are a minimum if they are then put in the following step if one is then put that and forget the other ,put the values in f(x) and see if u get negative answer which u shudnt as f(x) stays positive !
this proves that the graph never went beyond x axis and was always +,u use stationary values to find the values of x for minimum points because these values have f(x) at the lowest value so if they dont give u minus nothing will
U will get a cubic equation so u will need to solve it (hahaha thats why i didnt solve it its really boring )
For the other one try it urself it really is straightforward,u need to use those different forms of expressing complex no. to get w then its quite easy ! Ill INSHAALLAH solve it tomorrow or soon as for now im really out of time sorry
thank you very very muchpart 4 (ii)
We know by part (i) that the factors are (x^2 +2x +2) (x^2 -4x +4)
to factorize (x^2 -4x +4)
this can be done as (x-2) ^2
then we d factorize (x^2 +2x +2)
we wud get ((x+1) ^2) +1)
now if we multiply ((x+1)^2) +1)) (x-2) ^2 all the negative terms wud be squared to give positive results thus
((x+1)^2) +1)) (x-2) ^2 > 0
ummm...its okay you don't have to do question 5 .....i got it nowin first one
after finding a put it in the equation and find its derivative,put the derivative as 0 so that u find the stationary values of x,now do double derivative and put these values of x and see if points are a minimum if they are then put in the following step if one is then put that and forget the other ,put the values in f(x) and see if u get negative answer which u shudnt as f(x) stays positive !
this proves that the graph never went beyond x axis and was always +,u use stationary values to find the values of x for minimum points because these values have f(x) at the lowest value so if they dont give u minus nothing will
U will get a cubic equation so u will need to solve it (hahaha thats why i didnt solve it its really boring )
For the other one try it urself it really is straightforward,u need to use those different forms of expressing complex no. to get w then its quite easy ! Ill INSHAALLAH solve it tomorrow or soon as for now im really out of time sorry
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