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Mathematics: Post your doubts here!

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Yes, I'm writing my paper this May. Difficulty is a relative term. The subject content is essentially an extension of the whatever you cover in P1, P3, M1/S1 and m2/S2 with a few new concepts. It's more difficult if you don't have prior S2/M2 knowledge in the sense that there is more subject matter that you have never previously dealt with. If you have a solid base in P1, P3 then the further pure math part shouldn't cause you much trouble. Personally I think the further mechanics is the easiest section. Since you won't have M2 you'll have to put in more work because you practically end up covering the M2 syllabus as well. I have the most trouble with the further statistic section but that's because I never really liked S1. In short, what I can say is that you really have to put in time and a lot of work if you want to get everything done as the syllabus is pretty lengthy. It's just not a subject you can put off for the last minute.
Also, you get to understand how difficult the paper is once you start the question paper. I won't sugar coat it but the first time I did mine I almost cried. The only consolation- like everything else, it gets easier with time.

Thanks for the input. Honestly the Calculus part won't be much of a problem for me in P3 apart from that.. Complex Numbers and Vectors would cause quite a lot of trouble if I am being honest... I like doing S1.. If it were upto me I'd have taken S1,S2 in A Levels.. but our school only does S1, M1 combo..

Well I am not planning on taking it .. cause I already have Maths, Physics, Chemistry and Computers.. Physics next year would be extremely tough so yeah.. It's a pretty much done deal that I won't be taking Further but was just curious about the course..
 
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Thanks for the input. Honestly the Calculus part won't be much of a problem for me in P3 apart from that.. Complex Numbers and Vectors would cause quite a lot of trouble if I am being honest... I like doing S1.. If it were upto me I'd have taken S1,S2 in A Levels.. but our school only does S1, M1 combo..

Well I am not planning on taking it .. cause I already have Maths, Physics, Chemistry and Computers.. Physics next year would be extremely tough so yeah.. It's a pretty much done deal that I won't be taking Further but was just curious about the course..

Oh, okay. Glad to help. :)
 
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Thanks for the input. Honestly the Calculus part won't be much of a problem for me in P3 apart from that.. Complex Numbers and Vectors would cause quite a lot of trouble if I am being honest... I like doing S1.. If it were upto me I'd have taken S1,S2 in A Levels.. but our school only does S1, M1 combo..

Well I am not planning on taking it .. cause I already have Maths, Physics, Chemistry and Computers.. Physics next year would be extremely tough so yeah.. It's a pretty much done deal that I won't be taking Further but was just curious about the course..
you have computers too :). hows p2 comming along :confused:
 
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minie23
Q 9 (i)
the y component of OA is 1 and for OB is 2
thus ratio is double
x component is p:4, and so p =2 ( half of 4 is 2)
proof is 1: P, p=2 (double the 1 is 2)

vector of OA is ( 2, 1, 1)
unit vector means divide each component with modulus
mod is sqrt(2^2 + 1^2 + 1^2) [read as : square root of 2 square plus 1 square plus 1square]
ans= sqrt6
unnit vector is
(2/s6, 1/s6, 1/s6) [P.S. s is square root]
 
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minie23
9 (iii)
i think it would be good to draw this, i drew this and answered as follow
Capture.PNG

for A to become O, (that is from 3,1,1 to 0,0,0)
u need to minus 3 for x component and minus 1 for y and z comp.

therefore for B to become C,
u minus x by 3 making 1
and for y you minus 1 making 1
and for z minus 1 making 2

C is then (1,1,2)
 
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minie23

Question 7 (ii) [P.S my answer isnt confirmed...dint find in ms]

they said to express inverse function in similar way.

First lets find the two inverses

first one. f(x) = 11 − x^2
y = 11 - x^2
x^2 = 11 - y
x = sqrt(11 - y)
therefore
f^-1 = sqrt(11-x)

second one is 5 − x
y = 5 - x
x= 5-y
therefore f^-1 = 5 - x

Now to find the domain of new functions, to do this we have to find the range of original functions.

we will start with second.
5-x for x>3 (p =3 from first part)
when x = 3 , y = 2
and when is 4 , y=1
so as x increase from 3 y decrease from 2
therefore y<2
therefore
the inverse domain is x<2

for first one...really hard to explain see..
11 − x^2 for 0 ≤ x ≤ p (p=3)
when x = 0
y is 11
when x = 3
y is 2
therefore
11 > y > 2 ( it is less and EQUAL to not only less than)

therefore first domain is 11 > x >2
 

Dug

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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_3.pdf

Q10(ii) and (iii). Can someone provide full working out? I would really appreciate it because I'm stuck :/
ii)
A = ⌡x² √(1 - x²) dx

x = sinΘ
dx = cosΘ dΘ

A = ⌡sin²Θ √(1 - sin²Θ) cosΘ dΘ
A = ⌡sin²Θ cos²Θ dΘ
A = ⌡(sinΘ cosΘ)(sinΘ cosΘ) dΘ
A = ⌡(½ sin2Θ)(½ sin2Θ) dΘ
A = ¼ ⌡sin² 2Θ dΘ

The curve touches the x-axis at 0 and 1.

Limits:
x = 0, Θ = 0
x = 1, Θ = π/2

iii)
A = 1/4 ⌡sin² 2Θ dΘ

cos 2Θ = 1 - 2sin² Θ
cos 4Θ = 1 - 2sin² 2Θ
sin² 2Θ = (1 - cos 4Θ)/2

A = ¼ ⌡(1 - cos 4Θ)/2 dΘ
A = 1/8 ⌡(1 - cos 4Θ) dΘ
A = 1/8 (Θ + ¼ sin 4Θ)

Insert limits:
A = 1/8 (π/2) = π/16
 
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s-03-qp-6 ques no 3 ii help plz
103-115/sd = z [sd=standard deviation, ]
-12/sd = -z
Capture.PNG
u see, the red area wanted, is identical to the area below the green.
therefore.
12/sd = z (with no negative sign)
the probablity of z is 80% (0.80)
from the table u find that z is 0.842

thus (-z) = -0.842
therefore -12/sd = -0.842
sd = 14.3
 
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Phy, chem, Bio, Math and English.
Not really. I applied for Imperial, so I thought having it might give me an edge and I like math so couldn't hurt.

Damn.. and here I thought my combination was difficult..

Further Maths, Bio, Chem, Physics, English.. one's mind would totally explode.. unless of course it's littlecloud11's mind :p
 
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