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okay the way i did this question is i used two equations then i used simultaneous equationshttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_42.pdf
Q3.
Explanation as well please x)
the equations i thought of and guessed they would help me are v = u +at and s = ut+1/2at^2....lets apply these equations to the motion through AB and BC
AB: V = u+at which is V= u+5a we also have 55= 5u + 12.5a
now lets take calculations for the motion from B to C....
BC: V2 = U2+5a and 65= 5U2+12.5a....now if u notice that U2 will be equal to V from because the final velocity of AB is the initial velocity of BC so U2= V(from the above equation)
65= 5(u+5a) +12.5a which is 65= 5u+37.5a...now u have two equations:
1. 55= 5u + 12.5a
2. 65= 5u+37.5a
use simultaneous equations and u will get a = 0.4 and u is 10...i hope u did get it now!