Mathematics: Post your doubts here!

[Scafalon40]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_33.pdf
Q9 (iii) and 10 part b ii PhyZac
last question for the day

 

[Shreeram]

Hi!! Can anyone help me to give a detailed explanation for june 12 p 42 q7 thanks

 

[PhyZac]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w09_qp_31.pdf

Please help for no. 10 (ii) & (iii)

okay first, move value to make two integration
(let ! be the integration sign)
dr/dt = 0.08r^2
1/r^2 dr = 0.08 dt
! 1/r^2 dr = !0.08 dt
! r^-2 dr = 0.08t +c
-1/r = 0.08t + c
sub values given in question
-1/5 = 0.08(0) + c
c = -1/5

-1/r = 0.08t - 1/5
r = -1 / (0.08 - 1/5)
r = -5 /0.4t - 1


Now for part iii
i am not sure
but what i think is the answer must be positive.
to do this the value shudnt be smaller than 0, (try calculating)
and even not more than 2.5
i got 2.5 by
0.4t-1 =0
0.4t =1
t= 2.5

 

[PhyZac]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_33.pdf
Q9 (iii) and 10 part b ii PhyZac
last question for the day

Okay i have the answering, but i dont know Q9 (i) if u can explain plzz.

so Q9 (iii)

If u got the a b values, 3 and 2

u sub them in the components.

3-λ = 4 + aµ
-2+2λ= 4 + bµ
1+λ = 2 - µ

so u get
3-λ = 4 + 3µ
-2+2λ= 4 + 2µ
1+λ = 2 - µ

choose any two and solve simultaneously

and u get µ = -1

no need to find λ or vice versa

take the value u got, i my case µ = -1
into its line equation and you willget
the i j k values.

about Q10 sorry i just saw it, will look into it, EDIT: i looked into it, i need to solve full question in order to answer tomorrow In Sha Allah

 

[Adorkableme]

I urgently need someone to solve Qs 1 from
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w08_qp_3.pdf

 

[PhyZac]

I urgently need someone to solve Qs 1 from
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_3.pdf

ln(x+2) = 2+lnx
ln(x+2) - lnx = 2
ln ((x+2)/x) = 2
(x+2)/x = e^2
x+2 = xe^2
xe^2 - x = 2
x(e^2 - 1) =2
x = 2/ (e^2 -1)
using calc.
x = 0.313

 

[immie.rose]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf

Q)4) help appreciated.


Anyone have trigonometry notes? Clearly my worst topic from P1.

You could try the trigonometry notes linked on the first page of this thread.
Here's what my guide says about the ques:

a: indicates the amplitude of the curve which is the max or min range of the curve from the mean position.
so, a=9-3=6

b: indicates the periodicity of the curve. we see that in the given figure there are two main cycles in a normal period of sine.
therefore, b=2

c: indicates the vertical shift in the graph from the horizontal axis, which in this case is 3 units.
thence, c=3 units

 

[unseen95]

please help me with question number 5(iii), shouldn't the two equations be
"0.1*1o - T = 0.1*a" and
"T - 0.8*0.5*10 = 0.5a"
if not what should the equations be and why? link to the question paper is http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s06_qp_4.pdf

 

[unseen95]

please help me with question number 6(i). Link to the question is http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s07_qp_4.pdf

 

[Scafalon40]

Okay i have the answering, but i dont know Q9 (i) if u can explain plzz.

so Q9 (iii)

If u got the a b values, 3 and 2

u sub them in the components.

3-λ = 4 + aµ
-2+2λ= 4 + bµ
1+λ = 2 - µ

so u get
3-λ = 4 + 3µ
-2+2λ= 4 + 2µ
1+λ = 2 - µ

choose any two and solve simultaneously

and u get µ = -1

no need to find λ or vice versa

take the value u got, i my case µ = -1
into its line equation and you willget
the i j k values.

about Q10 sorry i just saw it, will look into it, EDIT: i looked into it, i need to solve full question in order to answer tomorrow In Sha Allah

Thanks dude!
I'll wait for Q10
About Q9 (i):
set up the three equations:
3-t=4+q(a)
-2+2t=4+q(b)
1+t=2-q

t stands for lamda and q stands for 'mu'

Tidy up the equatins:
q(a)+t=-1..............................(1)
q(b)-2t=-6..............................(2)
q+t=1......................................(3)

now take the third equation and write it as t=1-q and substitute it in (1) and (2)

you'll get something like
qa+(1-q)=-1
qb-2(1-q)=-6

Now comes the part I won't solve XD
rearrange the equations to make q the subject and then equate them
et voila! you have your desired equation 2a-b=4!

EDIT: I'm so sorry dude I should've given you the heads up: the question is worth only one mark!
I just figured it out though: we have the values of a and b and we have those two equations with q as the subject. Just put a in the first one and you'll get q! Then use q for the point.
Sorry I wasted your time

 

[Yousif Mukkhtar]

Can some explain this Permutation question q5 a) ii)
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w09_qp_61.pdf

Why is it 1 x 6 ^ 3?

 

[syed1995]

Can some explain this Permutation question q5 a) ii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_61.pdf

Why is it 1 x 6 ^ 3?

This is not technically a permutation question since it won't require the P...

5000 and 6000 .. meaning it's a four digit number which starts with a 5.

so first number is 5.. that's a given.

5 _ _ _

Now since repetition is allowed..

the next 3 numbers can be anything from 1,2,3,4,5,6

meaning it can be 5555 5432 or 5646 .. all are possible.

so 6 choices for all the 3 other spaces..

meaning it becomes

1 * 6 * 6 * 6... = 1*6^3

 

[applepie1996]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w06_qp_3.pdf
question 7 part 4
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w05_qp_3.pdf
question 7 part 3
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w04_qp_3.pdf
question 9 part 3
PhyZac Rutzaba or anyone else

 

[daredevil]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_12.pdf

plz help me with question 11.
what approach can we apply to this question.... i have gone totally blank on this one

 

[iKhaled]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_12.pdf

plz help me with question 11.
what approach can we apply to this question.... i have gone totally blank on this one

this question is a nightmare to me..came in my exam and i ran out of time thinkin of it and it turned out to be a pretty stupid tricky question -_-

 

[minie23]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_12.pdf

plz help me with question 11.
what approach can we apply to this question.... i have gone totally blank on this one

(i) Transform OCR in a right-angled triangle.
Thus, you will CR = x cm , OC = 20 - x cm
The angle (q) COR will be 0.6 rads.

we have hypotenuse and opposite, we use, sin q = CR/OC
= sin(06) = x/(20-x)

I guess, you can proceed now !

 

[ElvinJc]

Can someone please explain Q2 part i & Q8 PART i to me? Please!
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w09_qp_32.pdf
THX

 

[Yousif Mukkhtar]

This is not technically a permutation question since it won't require the P...

5000 and 6000 .. meaning it's a four digit number which starts with a 5.

so first number is 5.. that's a given.

5 _ _ _

Now since repetition is allowed..

the next 3 numbers can be anything from 1,2,3,4,5,6

meaning it can be 5555 5432 or 5646 .. all are possible.

so 6 choices for all the 3 other spaces..

meaning it becomes

1 * 6 * 6 * 6... = 1*6^3

Thanks

 

[iKhaled]

hey..i need help with the last part of question 10 (b) i know how to sketch it and shade it but i cant find the max arg of z

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_32.pdf

 

[PhyZac]

Thanks dude!
I'll wait for Q10
About Q9 (i):

.............................
Now comes the part I won't solve XD
rearrange the equations to make q the subject and then equate them
et voila! you have your desired equation 2a-b=4!

EDIT: I'm so sorry dude I should've given you the heads up: the question is worth only one mark!
I just figured it out though: we have the values of a and b and we have those two equations with q as the subject. Just put a in the first one and you'll get q! Then use q for the point.
Sorry I wasted your time

Thank you sooooooooooooooo much for the Help, Jazaka Allah khairan!! May Allah S.W.T bless you with high grades Ameeen, and May Allah S.W.T have mercy on you and your family.
Okay to get the value answer Q10 U need to make sure u have done part b correctly..
it is in short, a circle in forth quadrant, and there is a line 1/4 pi below x axis and a line 1

Now in the sketch below. You see, the largest point is in purple point. And to find it first we find the length of blue line under the green lines, to this use pythagoras theorem , so the short blue line is √2^2 +2^2 = 2√ 2
now to find the blue line till the purple point add a radius , which is 2, 2+2√2
now to find the largest Real Number, we have to find the value of xaxis above the purple point,
we know the angle is 1/4pi
so cos (1/4pi) = adj/ 2+2√2
adj = 2+√2