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Thanks dude!Okay i have the answering, but i dont know Q9 (i) if u can explain plzz.
so Q9 (iii)
If u got the a b values, 3 and 2
u sub them in the components.
3-λ = 4 + aµ
-2+2λ= 4 + bµ
1+λ = 2 - µ
so u get
3-λ = 4 + 3µ
-2+2λ= 4 + 2µ
1+λ = 2 - µ
choose any two and solve simultaneously
and u get µ = -1
no need to find λ or vice versa
take the value u got, i my case µ = -1
into its line equation and you willget
the i j k values.
about Q10 sorry i just saw it, will look into it, EDIT: i looked into it, i need to solve full question in order to answer tomorrow In Sha Allah
I'll wait for Q10
About Q9 (i):
set up the three equations:
3-t=4+q(a)
-2+2t=4+q(b)
1+t=2-q
t stands for lamda and q stands for 'mu'
Tidy up the equatins:
q(a)+t=-1..............................(1)
q(b)-2t=-6..............................(2)
q+t=1......................................(3)
now take the third equation and write it as t=1-q and substitute it in (1) and (2)
you'll get something like
qa+(1-q)=-1
qb-2(1-q)=-6
Now comes the part I won't solve XD
rearrange the equations to make q the subject and then equate them
et voila! you have your desired equation 2a-b=4!
EDIT: I'm so sorry dude I should've given you the heads up: the question is worth only one mark!
I just figured it out though: we have the values of a and b and we have those two equations with q as the subject. Just put a in the first one and you'll get q! Then use q for the point.
Sorry I wasted your time