Mathematics: Post your doubts here!

[Rutzaba]

well i have both practicals and computing on my mind

but the thing is that i had no phy in alevels ... had it only in o and straight to uni phy, although its not a major... but still
i like phy jab tak practicals na hon -_-

 

[A star]

but the thing is that i had no phy in alevels ... had it only in o and straight to uni phy, although its not a major... but still
i like phy jab tak practicals na hon -_-

well it doesnt matter they do teach the basics in uni i guess :/
O are uni practicals hard :/

 

[Rutzaba]

they arent hard... but u need to have interest and u need to do it to aactually know it xD i used to sit back and enjoy lunch while my group member frends did the wrk

 

[Rutzaba]

and sussenly u have to do the practical all by ur self... seven pac revision in one day not to mention a viva that follows...andi also may have stats viva tommz but stats is bearable at uni level.. cux of so many vivas we have gud practice...

 

[A star]

they arent hard... but u need to have interest and u need to do it to aactually know it xD i used to sit back and enjoy lunch while my group member frends did the wrk

then i am glad we ha to single practicals the chem practicals seem fun at the start but physics seem borign from first day . sats viva ?

 

[Rutzaba]

we had alternate to practicals in o levels.. chemistry be love but only till the atps -_-

 

[Rutzaba]

cux it used tob sooooooooooooooooo easy

 

[A star]

i also had atps in O level started practicals this year

 

[Rutzaba]

lets not go off topic now

 

[salvatore]

According to the ms, no. But it would make your graph more accurate I guess.... and it's very simple, just replace y=0 and solve the eqn.

Well, I usually pay attention to x-axis, and as PANDA- said, easily by replacing y=0, the thing is, i forgot to do that when I replied to you.
To be safe side, do consider the x-axis.

So in this case its 1.966 radians => approx. 2/3π ? We just estimate the point on the graph right?

 

[Rutzaba]

then i am glad we ha to single practicals the chem practicals seem fun at the start but physics seem borign from first day . sats viva ?

hey wat was the frmula of finding acute angel between two tangents?

 

[iKhaled]

hey wat was the frmula of finding acute angel between two tangents?

tan theta = tangent

is that what you r lookin for ?

 

[Rutzaba]

i got wat i was looking for but sti dunno how to type it
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w08_qp_1.pdf

9 iii

 

[PANDA-]

i got wat i was looking for but sti dunno how to type it
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_1.pdf

9 iii

a^2 = b^2 + c^2 -2abcosq ... I guess? Lol
Would take some time because you'd have to find the point of intersection and then find the two lengths of the tangents from their respective points of tangency to the point of intersection (i hope this part is clear ) and find the length of c, the line between q and p... and then substitute.

Obviously there must be a shorter simpler way.

 

[Rutzaba]

i got wat i was looking for but sti dunno how to type it
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_1.pdf

9 iii

anyone helping?

 

[Rutzaba]

a^2 = b^2 + c^2 -2abcosq ... I guess? Lol
Would take some time because you'd have to find the point of intersection and then find the two lengths of the tangents from their respective points of tangency to the point of intersection (i hope this part is clear ) and find the length of c, the line between q and p... and then substitute.

Obviously there must be a shorter simpler way.

u guess wrong
tan theta= grad of one tangent
tan theta = gradient of second tangent
theta 1- theta 2 = answer
i dunno how to make the diagram is wayyy to complicated

 

[iKhaled]

i got wat i was looking for but sti dunno how to type it
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_1.pdf

9 iii

see..

dy/dx = tangent
tangent = y/x which is same as tan theta = y/x

so tan theta = dy/dx....find the gradient at point p and q by substituting the x values of p and q in the dy/dx u got (if u don't know how to differentiate tell me)

tan theta = 1.5 at point p and tan theta = 0.75 at point q
theta = 56.3 and 36.87
find the difference between the 2 56.3 - 36.87 = 19.4 and thats out answer!

i hope you got it

 

[Rutzaba]

see..

dy/dx = tangent
tangent = y/x which is same as tan theta = y/x

so tan theta = dy/dx....find the gradient at point p and q by substituting the x values of p and q in the dy/dx u got (if u don't know how to differentiate tell me)

tan theta = 1.5 at point p and tan theta = 0.75 at point q
theta = 56.3 and 36.87
find the difference between the 2 56.3 - 36.87 = 19.4 and thats out answer!

i hope you got it

wat no diagrams? ok heres one khalid to another MKh@lid

 

[iKhaled]

wat no diagrams? ok heres one khalid to another @mkh@MKh@lid

why do u need diagrams? and what is " @mkh@MKh@lid" :O:O

 

[Rutzaba]

why do u need diagrams? and what is " @mkh@MKh@lid" :O:O

see the edited version dude