Mathematics: Post your doubts here!

[shafayat]

alright man first of all you have to expand (1+ax)^6 using the binomial theorem ( i guess u have learnt that as it is part of ur syllabus) but not all of it like expand it up to the term x^3 onlyyy then expand (1-2x)^2 and multiply it with the answer u got when u did the binomial theorem..once u get an answer tell me..ok ? if u dont know how to use the binomial theorem then tell me also

Thanks man !! Got it ATLAST

 

[GorgeousEyes]

hello,
i need help on Question no 1 of 9709/11/m/j/10 (may june 2010 paper 11)
Thank you
please do reply!

you should know that tan (180-x) = -tan x .. (1)
and tan (90-x) = 1/ tanx .. (2)

i) if u used (1) --- > -k
ii) use ii --- >1/k
iii) by Pythagoras : tan = opp /adj thus tan = k/1 --> so hyp = ksquare+1square under square root
so sin =opp /hyp --> so k/= ksquare+1square under square root .

 

[shafayat]

what is the answer check the ms or tell which year u toook it from

Mayjune 2012 p11 Q7b(i)

 

[iKhaled]

Thanks man !! Got it ATLAST

 

[Hamza1996]

integrate dy/dx than put the values of x and y given in question to find C nd than thats ur equation

 

[Hamza1996]

Mayjune 2012 p11 Q7b(i)

integrate dy/dx than put the values of x and y given in question to find C nd than thats ur equation

 

[falcon678]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_42.pdf

guys question 7 part (i) anyone?
thanks

 

[PANDA-]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_42.pdf

guys question 7 part (i) anyone?
thanks

Finally a mechanics question lol. I was getting a bit rusty in mechanics. I'll try it and get back to you.

 

[falcon678]

Finally a mechanics question lol. I was getting a bit rusty in mechanics. I'll try it and get back to you.

m full of rust in mechanics....
thanks btw!

 

[iKhaled]

can someone pls explain to me question 11(ii) may june 2004 paper 3 mathematics
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s04_qp_3.pdf

i would really appreciate it if someone could draw for me the diagram of that question

 

[PANDA-]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_42.pdf

guys question 7 part (i) anyone?
thanks

Got it

Now at maximum speed, acceleration is 0, obviously because it can no longer go faster.
So you must differentiate to get the acceleration function, and equate it to 0, to get t.
First expand the velocity formula... from k(60t^2 - kt^3) to 60kt^2 - kt^3..
v = 60kt^2 - kt^3 ... Differentiate this.
a = 120kt - 3kt^2
120kt-3kt^2 = 0
120kt = 3kt^2

Divide both sides by kt

120 = 3t
t = 40

Now go back to the velocity function, and replace v with 6.4, as given in the question, and t with 40.

k(60(40)^2 - 40^3) = 6.4
k = 6.4/32000
k= 0.0002

 

[Alice123]

can someone pls explain to me question 11(ii) may june 2004 paper 3 mathematics
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s04_qp_3.pdf

i would really appreciate it if someone could draw for me the diagram of that question

i can do that without diag.. wait im doing it

 

[iKhaled]

i can do that without diag.. wait im doing it

thanks..i am still trying to do it ow and failing to answer it arghh :/

 

[Alice123]

d1=PQ=OQ-OP=(-2 4 1)-(1 0 -1)=(-3 4 1)
d2=PR=OR-OP=(4 2 1)-(1 0 -1)=(3 2 2)
Find the cross product of d1 and d2
ie ( 6 9 -18) it can also be written as (2 3 -6)
Now
rn=an
(x y z)(2 3 -6)=(3 5 -6)(2 3 -6) where a is OS( position vector of S)
the equatn is 2x +3y-6z=8

this is a very useful formula, try to remember it
modulus of (ax1+ by1+cz1-d)/root of (a^2+b^2+c^2) see winter 2012...its given there
mod of{(2(3)+3(5)-(-6)-8)}/root of(2^2+3^2+6^2)
and the ans comes to 7 units
if u dnt understand feel free to ask iKhaled

 

[rosogolla993]

wats up !! evry1

 

[rosogolla993]

Mashallah jajak allah khair

 

[Alice123]

iKhaled

 

[rosogolla993]

fi Amanillah

 

[GorgeousEyes]

Please Nov2012 v.13 no.6 i . no.7 ii , 8 iii ) , 9 all , 10 iii
11 ) ii and iv urgentlyyy .

 

[rosogolla993]

i need help in functions in p1 as