f(x)= 6 (2x+3)^-1
f'(x) = -6 (2x+3)^-2 (2+0)
-12/(2x+3)^2
-[12/(2x+3)^2]
whatever the value of x, whether negative or positive, the whole square will make the entire bracket value positive. but the negative sign will always make the answer negative so f(x) is always a decreasing function.
f'(x) = -6 (2x+3)^-2 (2+0)
-12/(2x+3)^2
-[12/(2x+3)^2]
whatever the value of x, whether negative or positive, the whole square will make the entire bracket value positive. but the negative sign will always make the answer negative so f(x) is always a decreasing function.