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y dun u refer to the answer paper ?Thanks. For 'Q6' how to do the second sub-part, http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_1.pdf
y dun u refer to the answer paper ?
nah sweety its not that. if u r getting the concept u shud be able to solve it urself na?Its okay if u got tired of answering
after you find out the equation of BC which turns out to be 3y+2x=20, substitute y=0 for C. So the coordinates are C(10,0). To find D, we know that AB is parallel to CD. So count the number of steps (i.e from A-B, the x-coordinate moves from -2 to 2, and y-coordinate from 8 to 14. So similarly, we move 4 units right and 6 units up from C to D) Voila!.... D(14, 6)
nah sweety its not that. if u r getting the concept u shud be able to solve it urself na?
thats how u learn
it shudnt be like that buddy. thses questions are quiet simpleIts easy in the book but when it comes to past papers I am blank
do this by using the opening formulas for sin( alpha- theta)3cos(2x-Y)+4sin(2x-Y)=2
find x 0 to 2pi
Y is theta
plz solve..do this by using the opening formulas for sin( alpha- theta)
and cos(alpha- theta)
have to integrate this?plz solve..
here`re the values of 2x-Y : -0.232, 2.09, 6.053cos(2x-Y)+4sin(2x-Y)=2
find x 0 to 2pi
Y is theta
Hello .. can u help me with this ...
Show that ,
integral of tan2x =1/2 Insec2x + c
i am not that good in integration ... every time we perform a new thing ! .. is there a specific formula which applies to all integrations .. help
integrate cos^2(x)
tell me procedure..here`re the values of 2x-Y : -0.232, 2.09, 6.05
tell me procedure..here`re the values of 2x-Y : -0.232, 2.09, 6.05
tan2x = sin2x/cos2x
integration of sin2x/cos2x = -0.5(ln(cos2x)+c = o.5ln(cos2x)^-1 +c = 0.5ln(sec2x) +c
use the double angle formula for this one
cos^2(x) = (cos2x+1)/2
tan2x = sin2x/cos2x
integration of sin2x/cos2x = -0.5(ln(cos2x)+c = o.5ln(cos2x)^-1 +c = 0.5ln(sec2x) +c
use the double angle formula for this one
cos^2(x) = (cos2x+1)/2
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