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Mathematics: Post your doubts here!

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tan2x = sin2x/cos2x
integration of sin2x/cos2x = -0.5(ln(cos2x)+c = o.5ln(cos2x)^-1 +c = 0.5ln(sec2x) +c



use the double angle formula for this one
cos^2(x) = (cos2x+1)/2

can u ( plz ) post some of the formulas ... because i first time hear of double angle formula ! >> formulas which are not inside the book
 
Messages
415
Reaction score
252
Points
53
tan2x = sin2x/cos2x
integration of sin2x/cos2x = -0.5(ln(cos2x)+c = o.5ln(cos2x)^-1 +c = 0.5ln(sec2x) +c



use the double angle formula for this one
cos^2(x) = (cos2x+1)/2

can u ( plz ) post some of the formulas ... because i first time hear of double angle formula ! >> formulas which are not inside the book
 
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∫ (1-x) (e^-0.5x)
can also be written as
∫ e^0.5x +∫ (-xe^-0.5x)
break this into 2 parts the first integral can be solved by
∫ (e^-0.5x) = -2e^-0.5x ---- i
the second part
∫ (-xe^-0.5x)
apply by parts
u=x and its differential u'=1
dv= e^-0.5x and its integral and v= -2e^ -0.5x
apply
∫ u dv= uv- ∫v du
-2x e^-0.5x + ∫ 2 e^-0.5x
-2x e^-0.5x -4e^ -0.5x ---- ii
i+ii
(wch is minus)
-2e^ -0.5x - (-2x e^ -0.5x -4e^ -0.5x)
(-2e^ -0.5x) +(2x e^ -0.5x) +(4e^ -0.5x)
Now apply limit 1 and 0 :)
and remember me in prayers plz i badly badly need it
 
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382
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∫ (1-x) (e^-0.5x)
can also be written as
∫ e^0.5x +∫ (-xe^-0.5x)
break this into 2 parts the first integral can be solved by
∫ (e^-0.5x) = -2e^-0.5x ---- i
the second part
∫ (-xe^-0.5x)
apply by parts
u=x and its differential u'=1
dv= e^-0.5x and its integral and v= -2e^ -0.5x
apply
∫ u dv= uv- ∫v du
-2x e^-0.5x + ∫ 2 e^-0.5x
-2x e^-0.5x -4e^ -0.5x ---- ii
i+ii
(wch is minus)
-2e^ -0.5x - (-2x e^ -0.5x -4e^ -0.5x)
(-2e^ -0.5x) +(2x e^ -0.5x) +(4e^ -0.5x)
Now apply limit 1 and 0 :)
and remember me in prayers plz i badly badly need it
Thanks s lot Rutzaba!!
I'll definitely remember you in prayers :)
 
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a girl lives 500 meter from school.she sets out walking at 2 m/s but when she has walked a distance of x meter her speed has dropped to (2 - x/400 )m/s .how long does she take to get to school?answer is 6.5 minute plz solve
 
Messages
676
Reaction score
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Points
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a girl lives 500 meter from school.she sets
out walking at 2 m/s but when she has
walked a distance of x meter her speed has
dropped to (2 - x/400 )m/s .how long does
she take to get to school?answer is 6.5
minute plz solve
 
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U need to square this quadratic equatiion: (x^2 -2x -3)

(x^2 - (2x+3) )^2 = x^2 - 2 (x)(2x+3) + (2x+3)^2


Now u can complete............
 
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