Mathematics: Post your doubts here!

[daredevil]

Guys need a help here.

m contains A and B means the vector AB is part of the plane m.
find the vector AB by : OB - OA
and if m is parellel to OC then vector of m should be a multiple of vector OC.
see if you get it... otherwise i'll try to explain further. sorry can't solve it right now.

 

[biscuitbiscuit]

t

when you expand ... add all cofficients of x ... and equate with zero to find a

thanks

 

[biscuitbiscuit]

sin^2θ - 3cos^2θ +1 /sin^2θ -cos^2θ =2

 

[periyasamy]

m contains A and B means the vector AB is part of the plane m.
find the vector AB by : OB - OA
and if m is parellel to OC then vector of m should be a multiple of vector OC.
see if you get it... otherwise i'll try to explain further. sorry can't solve it right now.

Thank u...

 

[periyasamy]

Guys anyone can give me a hand for both these questions.Thanks a lot
The answers are
(i)25 sin (θ– 16.26°);(ii)59.1°.

 

[panoramafolks]

Guys anyone can give me a hand for both these questions.Thanks a lot
The answers are
(i)25 sin (θ– 16.26°);(ii)59.1°.

(i) R = (7^2 + 24^2)^.5
= (49 + 576)^.5
= (625)^.5
= 25

a = tan^-1(7/24)
=16.26

(ii) 25 sin (θ– 16.26°) = 17
sin (θ– 16.26°) = 17/25
(θ– 16.26°) = sin^-1(17/25)
θ– 16.26° = 42.84
θ = 42.84 + 16.26= 59.1 °.

 

[Jessie N.]

someone please help. My friend asked me this and I dunno how to solve it :/ AS problem I think.

 

[ahmed abdulla]

(i) Show that 1/secx -tanx = secx + tanx
(ii) Find the REMAINDER ( not quotient ) when 8x^3 - 10x^2 -x +3 is divided by 2x^2 -1
Ans is 3x-2 but i get it as -2 only!

 

[panoramafolks]

(i) Show that 1/secx -tanx = secx + tanx
(ii) Find the REMAINDER ( not quotient ) when 8x^3 - 10x^2 -x +3 is divided by 2x^2 -1
Ans is 3x-2 but i get it as -2 only!

 

[daredevil]

(i) Show that 1/secx -tanx = secx + tanx
(ii) Find the REMAINDER ( not quotient ) when 8x^3 - 10x^2 -x +3 is divided by 2x^2 -1
Ans is 3x-2 but i get it as -2 only!

don't write it like 1/sec x -tan x because that reads like (1/secx) - tanx = ... and that is confusing and misleading. when writing the questions here please write it like (in this case) 1/(secx-tanx) = ...

Thank you

 

[snowbrood]

don't write it like 1/sec x -tan x because that reads like (1/secx) - tanx = ... and that is confusing and misleading. when writing the questions here please write it like (in this case) 1/(secx-tanx) = ...

Thank you

this confused me too all this time i thought mine trig's prep is not good hahaha

 

[daredevil]

this confused me too all this time i thought mine trig's prep is not good hahaha

hahaha exactly!! otherwise trig is the one question jis k marks THANK GOD merey confirm hotay hain and i was like DAYUMMN!

 

[periyasamy]

(i) R = (7^2 + 24^2)^.5
= (49 + 576)^.5
= (625)^.5
= 25

a = tan^-1(7/24)
=16.26

(ii) 25 sin (θ– 16.26°) = 17
sin (θ– 16.26°) = 17/25
(θ– 16.26°) = sin^-1(17/25)
θ– 16.26° = 42.84
θ = 42.84 + 16.26= 59.1 °.

Thank u a lot.

 

[m7aug]

find the stationary point from the double derivative. use equation to find the remaining coordinate of the stationary point.
the stationary point with a negative double derivative is the maximum point. one stationary point has y coordinate 0 so the other one will be at b. i hope u get it. consult the marking scheme along with the explanation. maybe u'll get it. if not then tell me and i'll elaborate further

thanks i got it

 

[m7aug]

How to find the coefficients of x and x^2 in the expansion of (4-x)(2-4x)^6

first of all expand (2-4x)^6 and at least first three terms and then use ur answer to multiply it with (4-x) . It will be something like this (4-x)(-786x+3840x^2) now only multiply the those terms which will give u a variable x^2 e.g 4(3840x^2) and (-x)(-786x) and we'll get 15360x^2 +786x^2 u can solve it to get the coof of x^2. Consult mark scheme it will make it more clear..got it

 

[♫Prince Shah♫]

Someone solve this please " The sixth term of an arithmetic progression is twice the third term, and the first term is 3. The sequence has ten terms. Find the common difference."

is common difference 3 ?

 

[♫Prince Shah♫]

Someone solve this please " The sixth term of an arithmetic progression is twice the third term, and the first term is 3. The sequence has ten terms. Find the common difference."

if c.d = 3

hence T6=2*T3
so, a+5d=2a+4d
a=3 that is given,
so, 3+5d=6+4d
therefore, d=3 you got your c.d Hope u understood it

 

[salvatore]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_41.pdf
Someone please help me with this mechanics question.
Qn no. 5(ii).. why is the kinetic energy greater than potential energy?

Thanks

 

[TheZodiac]

Variables of X and Y are related by the differtial equation
( x^2 + 4 ) ( dy/dx ) =6xy
it's given that y=32 when x=0 . Find an expression for y in terms of x

Separate the variables and this would lead to an equation of
1/y dy = 6x/x^2 +4 dx
Integrate it and then put the values x and y which would result in your getting 'c'. Then express the equation in terms of x for y

 

[simohayak]

I have a doubt regarding a differentiation sum of the following form:
The equation : (X^3 + XY^2 + aY^2 - 3aX^2=0) is given. Where a is a positive constant. The maximum point on the curve is M. How do i find the x coordinate of M? in terms of "a"