Mathematics: Post your doubts here!

[Altamash Haroon]

Tha

i)
If Two Vector A and B are collinear (on the same line).. then Vector B = k(Vector A)

OA = (p, 1, 1) OB = (4, 2, p)

Comparing the j coefficents ..

OB = k(OA)
2 = k(1)
k=2

now compare either of the first or last to get p... Like comparing the first one we get

OB = k(OA)
OB = k(OA)
4= 2(p)
p=2 Answer

Unit vector in direction of OA vector :¬
As we know P = 2, hence, OA vector = (2, 1, 1)
So, 1/roof(2^2 + 1^2 + 1^2) = 1/root(6)


iii)
What you dont get in this? Simply do OB - OA.

Thanks a ton!!

 

[♣♠ Magnanimous ♣♠]

All the best to all of the members who have exam tomorrow!
Write exam well and get good grades
Don't be nervous! Calm down and I think the day before papers should be enjoyment so that our mind get fresh and we don't get confuse in formulas and bla bla bla bla

 

[Thought blocker]

Yeah, all the best all. ^_^

 

[♣♠ Magnanimous ♣♠]

Yeah, all the best all. ^_^

 

[Abdel Moniem]

http://onlineexamhelp.com/wp-conten...wp-content/uploads/2014/08/9709_s14_qp_11.pdf
Q10 ii) and iii) and Q11 ii)

 

[ZîîHana Kawaîî]

http://onlineexamhelp.com/wp-conten...wp-content/uploads/2014/08/9709_s14_qp_11.pdf
Q10 ii) and iii) and Q11 ii)

error 404 page not found :S dont u hve another link?

 

[Abdel Moniem]

error 404 page not found :S dont u hve another link?

http://justpastpapers.com/cie-a-level-mathematics-paper-1-9709-pure-mathematics-1-past-papers/

 

[ZîîHana Kawaîî]

QU 10 ii) sketch the inverse of f(x) tht is reflection on y=x

iii) let f(x) = y
make x subject of formula
then f inverse = the equation in terms of y but replace the y by x
do this for both equations

as for the set of values
range of f(x) = domain f inverse
domain of f(x)= range of f inverse
whn sketching the graph ull find it

its -5<x<1 and 1<x<4 as far as i remember...i did it this morning

 

[ZîîHana Kawaîî]

QU 11
replace c by 11 on line
solve curve n line simultaneously...ull get x coordinates
integral of line - integral of curve
solve for limits which are the x coordinates found whn solved simultaneously
put modulus if it becomes negative

 

[Thought blocker]

http://onlineexamhelp.com/wp-conten...wp-content/uploads/2014/08/9709_s14_qp_11.pdf
Q10 ii) and iii) and Q11 ii)

RoOkaYya G and Rutzaba help.

 

[Abdel Moniem]

QU 10 ii) sketch the inverse of f(x) tht is reflection on y=x

iii) let f(x) = y
make x subject of formula
then f inverse = the equation in terms of y but replace the y by x
do this for both equations

as for the set of values
range of f(x) = domain f inverse
domain of f(x)= range of f inverse
whn sketching the graph ull find it

its -5<x<1 and 1<x<4 as far as i remember...i did it this morning

Thank you so much

 

[ZîîHana Kawaîî]

RoOkaYya G and Rutzaba help.

i already replied to this. y r u asking help for this again?

 

[ZîîHana Kawaîî]

Thank you so much

pleasure

 

[Thought blocker]

i already replied to this. y r u asking help for this again?

I never saw sorry.

 

[Thought blocker]

I still remember this : https://www.xtremepapers.com/commun...st-your-doubts-here.9599/page-607#post-763127

 

[Haya Ahmed]

Guys is it acceptable to multiply 2^x (into) 3^x to be 6^x ??

 

[Kamihus]

Guys is it acceptable to multiply 2^x (into) 3^x to be 6^x ??

Yes.

 

[Thought blocker]

Guys is it acceptable to multiply 2^x (into) 3^x to be 6^x ??

I am not sure whats in that pic, but Rutzaba will tell you after looking into it.. btw its 6x^2

 

[Thought blocker]

Yes.

Come on! Really?

 

[Kamihus]

Come on! Really?

Didn't check the question, just said that 2^x*3^x is 6^x. Just Plug in some values to make sure.