- Messages
- 1,432
- Reaction score
- 6,887
- Points
- 523
wait! ill re do it.
*sigh*
*sigh*
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Ok please just differentiate that one equation,it would be enough!=Pi saw jst ur post n corrected it there.
wait lets take it from beginning! ok?
OMG!!! im so sorry!! i misread. its x^2 in the equation i used x^3
nxt time plz put ur attachments upright -_______- thank u
i got it *sigh*Ok please just differentiate that one equation,it would be enough!=P
Dont worry i got it!I did it no needi got it *sigh*
PLEASE NEXT TIME UPRIGHT ATTACHMENT
thts betterDont worry i got it!I did it no need
Thanks a lot you're a legend!I'm sure you have an A* in store for your maths exam!dV/dx = dV/dt * dt/dx
PS: the 6 is mentioned to beautify the quest only
simplifying the equation :
6pi*x^2 - (pix^3) /3
differenciating it :
12pix-pix^2
when x= 2
dV/dx= 20 pi
replacing in chain rule :
20 pi =3* dt/dx
dt/dx =20pi/3
dx/dt = 3/20pi <---------ANSWER
Thanks for your help !! I got it now !! RoOkaYya G40)
R = square root ( 1^2 + 1 ^2) = square root 2
alpha :
tan alpha = 1/1
alpha=tan inverse 1
= pi/4
Rcos (theta + alpha) = square root 2 (theta + pi/4) <----------ANSWER
cos theta + 1/ root 2 = sin theta
cos theta- sin theta = - 1 / root 2
Rcos (theta + alpha) = - 1 / root 2
square root 2 (theta + pi/4) = - 1 / root 2
solve for theta :
cos (theta+ pi/4) = - 0.5
(theta+ pi/4) = cos inverse 0.5
(theta+ pi/4) = pi/3
cos is negative so in quadrant S and T
in quadrant S (theta+ pi/4) = (pi -pi/3) = 2pi/3
in quadrant T (theta+ pi/4) = pi + pi/3 = 5 pi/3
theta = (2pi/3 - pi/4) and (5pi/3- pi/4)
=5pi/ 12 and 14pi/12
for acute angle, theta = 5pi/12 <---------------- ANSWER
44) ii) b)
solving part i) ull get it in R cos form as :
25sin(theta +73.7)....using this derive 25 cos (theta -73.7)
25 cos (theta-73.7) = -3
cos (theta-73.7) = -3/25
(theta-73.7) = cos inverse (3/25)
since cos is negative the solutions r found in S andT quadrant
in S, (theta-73.7) = 180 -83.1 = 96.9
in T,(theta-73.7) =180+ 83.1 = 263.1
(theta-73.7) =96.9 and 263.1
theta =(96.9+73.7) and (263.1 +73.7)
theta= 170.6 and 336.8
theta = 170.6 for 0< theta< 180 <-----------ANSWER
45)
equate the give equation of tan theta to 1/5
cross multiply
ull get x^2 +384 =5(8x)
x^2 + 384-40x =0
x^2 -40x +384 = 0
solving the quadratic :
(x-16)(x-24) =0
x= 16 and x=24 <------------ANSWER
ill post 46 in a while dinner
legend? y u say so? :OThanks a lot you're a legend!I'm sure you have an A* in store for your maths exam!
lol,no sarcasm,i'm just really impressed,no one in my class got this one right so i meant it ^^legend? y u say so? :O
was that sarcasm? :/
if u meant it then thanks loads! ^_^ In Sha Allah ^_^
i wish u the same u had an awesome As result keep it up! ^_^
look. the equations given above...there was 7sin theta...Thanks for your help !! but can you explain 44 ii) b once more in detailed because I didn't get it !
hmm oklol,no sarcasm,i'm just really impressed,no one in my class got this one right so i meant it ^^
Yeah our sir said the same,but actually we were all confused by the 6 and tried to insert it somehow in our answers so thats why we were wrong :/hmm ok
actually i read it wrong at first thts y i got the wrong answer whch was close enough
its a direct question no need to panic
whnever theres rate of change....write down a chain rule at first. note down all the infos given. then as per ur chain rule. find the missing parts n replace n solve
yeah they do CIE likes to screw up with studentsYeah our sir said the same,but actually we were all confused by the 6 and tried to insert it somehow in our answers so thats why we were wrong :/
In CIEs do they also give useless information?Cuz in o lvls all the info we had was to be used in some way,so thats why we thought we had to include 6.
i guess the question u gave...had other parts too...where the 6 shuldve been used.yeah they do CIE likes to screw up with students
but u dont worry about it. u need to be focussed n know the steps. dont bother about additional information
well in question Q45 how did .. you get the equation 8x/x^2 +384 ... ?!40)
R = square root ( 1^2 + 1 ^2) = square root 2
alpha :
tan alpha = 1/1
alpha=tan inverse 1
= pi/4
Rcos (theta + alpha) = square root 2 (theta + pi/4) <----------ANSWER
cos theta + 1/ root 2 = sin theta
cos theta- sin theta = - 1 / root 2
Rcos (theta + alpha) = - 1 / root 2
square root 2 (theta + pi/4) = - 1 / root 2
solve for theta :
cos (theta+ pi/4) = - 0.5
(theta+ pi/4) = cos inverse 0.5
(theta+ pi/4) = pi/3
cos is negative so in quadrant S and T
in quadrant S (theta+ pi/4) = (pi -pi/3) = 2pi/3
in quadrant T (theta+ pi/4) = pi + pi/3 = 5 pi/3
theta = (2pi/3 - pi/4) and (5pi/3- pi/4)
=5pi/ 12 and 14pi/12
for acute angle, theta = 5pi/12 <---------------- ANSWER
44) ii) b)
solving part i) ull get it in R cos form as :
25sin(theta +73.7)....using this derive 25 cos (theta -73.7)
25 cos (theta-73.7) = -3
cos (theta-73.7) = -3/25
(theta-73.7) = cos inverse (3/25)
since cos is negative the solutions r found in S andT quadrant
in S, (theta-73.7) = 180 -83.1 = 96.9
in T,(theta-73.7) =180+ 83.1 = 263.1
(theta-73.7) =96.9 and 263.1
theta =(96.9+73.7) and (263.1 +73.7)
theta= 170.6 and 336.8
theta = 170.6 for 0< theta< 180 <-----------ANSWER
45)
equate the give equation of tan theta to 1/5
cross multiply
ull get x^2 +384 =5(8x)
x^2 + 384-40x =0
x^2 -40x +384 = 0
solving the quadratic :
(x-16)(x-24) =0
x= 16 and x=24 <------------ANSWER
ill post 46 in a while dinner
i tld u there...we cross mutiply. the equation given in form of tan...and the 1/5well in question Q45 how did .. you get the equation 8x/x^2 +384 ... ?!
well I want to know where did we actually use the formula tan(A-B) and what is A and what is B ?i tld u there...we cross mutiply. the equation given in form of tan...and the 1/5
we dint use compound angle here drwell I want to know where did we actually use the formula tan(A-B) and what is A and what is B ?
the whole question was a nice story. but it was there to scare uwell I want to know where did we actually use the formula tan(A-B) and what is A and what is B ?
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now