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Mathematics: Post your doubts here!

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the whole question was a nice story. but it was there to scare u :p

u jst need to equate the equation give AS IT IS!!! to 1/5 (no need to apply compound angle formula or whtever....)
well .. so this story was to scare me ? ... even the part which said use formula tan(A-B) ? :D .. I know the equating part and how to get the ans but my question is why da hell did they say use this formula ? :p
 
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Haya Ahmed
taking the horizontal section of the corridor :
W = xcos theta + b sin theta

adjacent =cos theta * hypotenus

=xcos theta
opposite of smaller triangle = sin theta * b

=bsin theta

w= xcos theta + bsin theta
(HENCE SHOWN)

the side W = the adjacent side of the line AD (when taken in a triangle) + the opposite side of angle theta
so :

calculating the the adjacent side of the line AD (when taken in a triangle) :
the adjacent side of the line AD (when taken in a triangle)
cos theta =adjacent/ hypotenus
adjacent=cos theta * hypotenus =cos theta * b
=bcos theta


calculating the opposite side of angle theta :
sin theta = opposite/ hypotenus
hypotenus = length a of rectangle - part x of side CD
= a-x
sin theta = opposite / (a-x)
opposite = (a-x) *sin theta


HENCE , w= b cos theta + (a-x) sin theta
<--------- ANSWER

ii)
im unable to do ths part :S sorry

iii)
replace 45 - phi in the equation in part (ii) which is already given
use compound angle to expand and reach the solution asked there

iv) replace the values given in the equation given in part (iii)
solve for theta

ina hurry so plz manage :)
if u still dont get it then tell me :) for part iii and iv
ill do it stepwise

for (ii) im missing smethng i thnk. ill try it again later if u still dont get it. try ask someone else :)
well I'm lost here too .. which one is adjacent which is hypotenus ?! :D ... for the 1st part
 
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well I'm lost here too .. which one is adjacent which is hypotenus ?! :D ... for the 1st part
btw for the 45 ...im unable to derive it from tan(A-B)

the B is obviously the theta. the A is the whole angle (the theta + the angle beside it)
expanding the tan formula...i tried to replace n all..but im unable to get tht :(
im ina hurry too...try ask smeone else...
if not..
ill re try it later.
 
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try figure out a right angle triangle with the 2 sides already given na :whistle:
I still didn't get it , I'm sorry I'm disturbing you but if you can just use paint to show me the triangles where u used them to get xcos theta and bsin theta ! :)

ZuwDHT.jpg
 
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