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Haya Ahmed
taking the horizontal section of the corridor :
W = xcos theta + b sin theta
adjacent =cos theta * hypotenus
=xcos theta
opposite of smaller triangle = sin theta * b
=bsin theta
w= xcos theta + bsin theta (HENCE SHOWN)
the side W = the adjacent side of the line AD (when taken in a triangle) + the opposite side of angle theta
so :
calculating the the adjacent side of the line AD (when taken in a triangle) :
the adjacent side of the line AD (when taken in a triangle)
cos theta =adjacent/ hypotenus
adjacent=cos theta * hypotenus =cos theta * b
=bcos theta
calculating the opposite side of angle theta :
sin theta = opposite/ hypotenus
hypotenus = length a of rectangle - part x of side CD
= a-x
sin theta = opposite / (a-x)
opposite = (a-x) *sin theta
HENCE , w= b cos theta + (a-x) sin theta <--------- ANSWER
ii)
im unable to do ths part :S sorry
iii)
replace 45 - phi in the equation in part (ii) which is already given
use compound angle to expand and reach the solution asked there
iv) replace the values given in the equation given in part (iii)
solve for theta
ina hurry so plz manage
if u still dont get it then tell me for part iii and iv
ill do it stepwise
for (ii) im missing smethng i thnk. ill try it again later if u still dont get it. try ask someone else
taking the horizontal section of the corridor :
W = xcos theta + b sin theta
adjacent =cos theta * hypotenus
=xcos theta
opposite of smaller triangle = sin theta * b
=bsin theta
w= xcos theta + bsin theta (HENCE SHOWN)
the side W = the adjacent side of the line AD (when taken in a triangle) + the opposite side of angle theta
so :
calculating the the adjacent side of the line AD (when taken in a triangle) :
the adjacent side of the line AD (when taken in a triangle)
cos theta =adjacent/ hypotenus
adjacent=cos theta * hypotenus =cos theta * b
=bcos theta
calculating the opposite side of angle theta :
sin theta = opposite/ hypotenus
hypotenus = length a of rectangle - part x of side CD
= a-x
sin theta = opposite / (a-x)
opposite = (a-x) *sin theta
HENCE , w= b cos theta + (a-x) sin theta <--------- ANSWER
ii)
im unable to do ths part :S sorry
iii)
replace 45 - phi in the equation in part (ii) which is already given
use compound angle to expand and reach the solution asked there
iv) replace the values given in the equation given in part (iii)
solve for theta
ina hurry so plz manage
if u still dont get it then tell me for part iii and iv
ill do it stepwise
for (ii) im missing smethng i thnk. ill try it again later if u still dont get it. try ask someone else