Mathematics: Post your doubts here!

[DangerXJeff]

hey guys!
I'm stuck on this one question from http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_11.pdf
question 10 (ii) and (iii) can anyone help me with this.... any help will be appriciated

 

[Thought blocker]

hey guys!
I'm stuck on this one question from http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_11.pdf
question 10 (ii) and (iii) can anyone help me with this.... any help will be appriciated

Q10 i and ii Here

 

[neha saleem]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w09_qp_31.pdf q 2.....wid addng log cn any1 show.......

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_31.pdf q 2.....wid addng log cn any1 show.......

Q2 here

 

[Haya Ahmed]

Guys please help me to do this question

 

[Thought blocker]

Guys please help me to do this question

I solved this type of question first as well. Check it out Haya.
I guess it was your previous question on Integration. Btw where u get these questions from?
Are they from SAT II? (I know SAT II isn't easy though might be asked in 2 or 3 marks )
Is the answer [√(3) - 1]/2 ?

 

[Haya Ahmed]

I solved this type of question first as well. Check it out Haya.
I guess it was your previous question on Integration. Btw where u get these questions from?
Are they from SAT II? (I know SAT II isn't easy though might be asked in 2 or 3 marks )
Is the answer [√(3) - 1]/2 ?

yeah the answer is right !! .. now tell me how to do it ! these questions are from nabel elias book .. (Egyptian Maths doctor !

 

[Thought blocker]

yeah the answer is right !! .. now tell me how to do it ! these questions are from nabel elias book .. (Egyptian Maths doctor !

Check few back pages I solved there an integration problem before of the same type. As I am busy in my question
Or try : http://sh.st/io38L
If u wanna learn : http://sh.st/io4nQ (Module 5)

 

[Haya Ahmed]

Thought blocker please explain without this site because I DON'T get it from there

 

[Thought blocker]

Thought blocker please explain without this site because I DON'T get it from there

Haha, then u need to wait or try yourself from the tutorials I gave you. I will take a day as busy solving my own question.

 

[The Sarcastic Retard]

Any one please?

If u just take first term u get =1/2
If u add first two terms=1/2+2/6=5/6
Similarly for sum of three terms=1/2+2/6+3/24=23/24
...............sum of four terms= 1/2+2/6+3/24+4/120=119/120

So if u observe the pattern of sums
1/2, 5/6, 23/24, 119/120...........

So general formula for the sum would be
= ((n+1)!-1) /(n+1)!

= 1 - 1/(n+1)!
If n tends to infinity 1/(n+1)! = 0
Therefore Sum to infinity of the series is 1.

 

[Thought blocker]

Thought blocker please explain without this site because I DON'T get it from there

Ok I compared my solution with the site. Its almost same. I use my concept here that's it. Answer is same. Tell me what you dont get in it?

 

[neha saleem]

Q2 here

jst awsum xpln..........thnx..........

 

[Thought blocker]

jst awsum xpln..........thnx..........

No probs!

 

[DangerXJeff]

Q10 i and ii Here

Thanks alot bro...

 

[Thought blocker]

Thanks alot bro...

Welcomyy

 

[ARAJA96]

Somebody help me with A2 trigonometry differentiation and integration, i need notes or someone could make me understand them.

 

[Rohaan Nadeem]

pari ii

 

[Thought blocker]

Somebody help me with A2 trigonometry differentiation and integration, i need notes or someone could make me understand them.

http://sh.st/io4nQ
Look at chapters : 3, 4, 5. I bet you wont have any more doubts in it. But watch all the tutorials very carefully no matter how long it takes as you should build a very powerful concept in your mind that you dont need to revise anytime. All the best.

 

[Thought blocker]

pari ii

Tell me if it is incorrect but 99.0% it is correct if u ignore my paint skills
Here