• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

Messages
354
Reaction score
529
Points
103
I just know one thing here :
f (x) = sin (x) / x

dy/dx = [ d/dx (sin (x) ) * x - (sin (x) ) * d/dx (x) ] / x²

dy/dx = [ cos (x) * x - (sin (x) ) ] / x²

dy/dx = [ xcos (x) - sin (x) ] / x²

dy/dx = ( x cos (x) / x² ) - ( sin (x) / x² )

dy/dx = ( cos (x) / x ) - ( sin (x) / x² )
LOL ... you didn't take numerical solutions ? :D
 
Messages
20
Reaction score
3
Points
13
abcde credits. (Part ii)
i)
T = F and F = μR
T = μR
From the figure you can see T = 2N and R = 3N and μ = T/R = 2/3
tension-png.3793

ii)
As the system is in limiting equilibrium, the tension would equal A's weight i.e. 2N.
As A is about to move upwards, B is about to move rightwards. So the frictional force now will be in the same direction as the tension.
First, analyse the vertical forces.
In equilibrium, R + 1.8 = 3. => R = 1.2 N.
Considering forces horizontally, X = 2 + 2/3 (1.2) = 2.8 N.

Thank you!!!
 
Messages
20
Reaction score
3
Points
13
Help with these questions pleasee
 

Attachments

  • Captura de ecrã 2014-11-13, às 22.08.00.png
    Captura de ecrã 2014-11-13, às 22.08.00.png
    95.9 KB · Views: 12
  • Captura de ecrã 2014-12-2, às 19.13.55.png
    Captura de ecrã 2014-12-2, às 19.13.55.png
    74.5 KB · Views: 9
  • Captura de ecrã 2014-12-2, às 19.14.29.png
    Captura de ecrã 2014-12-2, às 19.14.29.png
    56.7 KB · Views: 7
  • Captura de ecrã 2014-12-2, às 19.14.53.png
    Captura de ecrã 2014-12-2, às 19.14.53.png
    34.1 KB · Views: 8
Top