Mathematics: Post your doubts here!

[Hassan Ali Abid]

For solved past papers, I did search, but they really aren't available online yet...A few sites are updating solved papers, but as I told you, there really is no chance for S2,...I found solved ones for Mechanics, and many other subjects, but no Statistics ....

Probability using venn diagram is explained in the book, but that's only for understanding of 'combined events' and mutually exclusive events etc, but there is no practice for these...it would be better if you have a look at the book yourself... the link doesn't work? works fine for me though..okay try to open this:
http://www.aliensservices.com/A_Level_Books.html

Then isnt there any other book having explaining everything with solved/worked examples ??

the link opens and all I can see is the page loading but not opening.

 

[bakhita]

Then isnt there any other book having explaining everything with solved/worked examples ??

the link opens and all I can see is the page loading but not opening.

Oh!! try this link:
http://www.gceguide.com/Books/ebs/e...orked_Examples__Fourth_Edition-JUGG3RNAUT.pdf

this will work!

 

[Hassan Ali Abid]

Oh!! try this link:
http://www.gceguide.com/Books/ebs/e...orked_Examples__Fourth_Edition-JUGG3RNAUT.pdf

this will work!

Yes It's working..Thanks a lot.

 

[bakhita]

Yes It's working..Thanks a lot.

no prob!

 

[Anum96]

NO..nothing as such is given in the question.

No. It wouldve been easier with a substitution though.
But The reason is that d(arctan x)/dx = 1/(1+x^2)

and the integral is the opposite of the derivative

 

[Hassan Ali Abid]

No. It wouldve been easier with a substitution though.
But The reason is that d(arctan x)/dx = 1/(1+x^2)

and the integral is the opposite of the derivative

but how is it possible to solve that with substitution ? and which substitution will be used?

 

[Anum96]

NO..nothing as such is given in the question.

Its not possible without substitution. Take substitution y = tanx or no. I dont understand it

Tbh Ive never been more baffled.

 

[Anum96]

but how is it possible to solve that with substitution ? and which substitution will be used?

If you applied the correct identity it might help . . . tan2(x)+1=sec2(x) Your integral equation then becomes, ∫1x2+1dx=∫dθ

^^This is what a teacher said.

 

[Wolfgangs]

Can someone please help me with this question

 

[Anum96]

Can someone please help me with this question

Is it choice A?

 

[Wolfgangs]

Can someone please help me with this question?

 

[sj0007]

Can anyone tell me the answers to this question?

 

[Sarosh Jameel]

PLZ help me with part 2 !!

 

[Anum96]

PLZ help me with part 2 !!

ii)Take 2 out.

2 ʃ ((2-u)^2 / u) du

Solve the square.

2 ʃ (4 - 4u +u^2)/u

Make fractions.

2 ʃ 4/u – 4u/u + u^2 /u)

Cancelling out will give you.

2 ʃ 4/u – 4 + u

Now integrate.

2 [ 4ln IuI – 4u + u^2/2 ]

8ln IuI - 8u + u^2

Plug in the limits.

(8ln I2I – 8(2) + (2^2)) – (8ln I1I – 8(1) + 1^2)

(8ln I2I – 16 + 4) – (0 – 8 + 1)

(8ln I2I – 12) – ( - 7)

8ln I2I - 12 + 7

8ln I2I – 5 Ans.

 

[Anum96]

Can anyone tell me the answers to this question?

View attachment 57697

Just the answers?
i) 106.3
ii) 7.2 N

 

[sj0007]

Just the answers?
i) 106.3
ii) 7.2 N

Yeah....... THNX!!!!!!
I did the ques but I couldn't find the answers anywhere......... Just wanted to confirm........ Thnx

 

[Anum96]

Yeah....... THNX!!!!!!
I did the ques but I couldn't find the answers anywhere......... Just wanted to confirm........ Thnx

Anytimee.

 

[sj0007]

Anytimee.

Awww Oki

 

[***amd***]

Can anyone tell me the answers to this question?

View attachment 57697

i) 106.26
ii) 7.2

 

[Sarosh Jameel]

ii)Take 2 out.

2 ʃ ((2-u)^2 / u) du

Solve the square.

2 ʃ (4 - 4u +u^2)/u

Make fractions.

2 ʃ 4/u – 4u/u + u^2 /u)

Cancelling out will give you.

2 ʃ 4/u – 4 + u

Now integrate.

2 [ 4ln IuI – 4u + u^2/2 ]

8ln IuI - 8u + u^2

Plug in the limits.

(8ln I2I – 8(2) + (2^2)) – (8ln I1I – 8(1) + 1^2)

(8ln I2I – 16 + 4) – (0 – 8 + 1)

(8ln I2I – 12) – ( - 7)

8ln I2I - 12 + 7

8ln I2I – 5 Ans.

Thanks a lot