(0.1+0.5)/2View attachment 57742
Can you show me how to do it for this one ?
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(0.1+0.5)/2View attachment 57742
Can you show me how to do it for this one ?
Yes. If there is a consistent .1 differenceif it was 2.8<=x<3, is the midpoint 2.8+2.9/2 ?
i guess it will still be 2.8+3.0 / 2, no? coz there might be values between 2.9 and 3 in the dataYes. If there is a consistent .1 difference
1/8Thank you
View attachment 57744
What is the probability of meal served on time and kitchen in a mess ?
0.1Thank you
View attachment 57744
What is the probability of meal served on time and kitchen in a mess ?
I dont think so. Just a less than sign means 3 isnt included. But if the next data value starts with 4 or 3. something then yesi guess it will still be 2.8+3.0 / 2, no? coz there might be values between 2.9 and 3 in the data
Umm I just completed the table. You get the second value of the last column by; 1 - (1/5). You get 0.8. Then you have been given the probability of kitch in a mess. Which is the third value of first column(3/5). You get the third value of second column by; 1 - (3/5). You get 0.4.how did you get 0.1 ?
1/8
like u multiply total of 'meal on time' with total of 'kitchen left on mess'
oh sorry i didnt see that 3/5 in the question. my badUmm I just completed the table. You get the second value of the last column by; 1 - (1/5). You get 0.8. Then you have been given the probability of kitch in a mess. Which is the third value of first column(3/5). You get the third value of second column by; 1 - (3/5). You get 0.4.
Calculate the first value of the second column. You get 0.1 (0.4 - 0.3) And then lastly, The requirement. 1/5 - 0.1 is 0.1
Dont take into account the whole probability. because that way your ans will include kitchen with no mess and not served on time 's probability too.if you actually calculate each probability you get a different answer. for example probability of meal served on time and kitchen is a mess = (1/5)*(3/5)=0.12. why are the answers different ?
didnt quite get you there. can u plz explain?Dont take into account the whole probability. because that way your ans will include kitchen with no mess and not served on time 's probability too.
In this question, we cannot use that method since the answer will take into account 'meal not served on time' and 'kitchen with no mess' 's probability as well. We need to determine the required probability separately. In other words, question is not asking for total. I hope I'm coherent enough. :/didnt quite get you there. can u plz explain?
didnt get it. Will try on it later again.In this question, we cannot use that method since the answer will take into account 'meal not served on time' and 'kitchen with no mess' 's probability as well. We need to determine the required probability separately. In other words, question is not asking for total. I hope I'm coherent enough. :/
Ill try one more timedidnt get it. Will try on it later again.
thanks btw
lol. still didnt get it.Ill try one more time
Its probably a conditional probability question :/
Because meal served on time WHEN theres mess made gives 0.1
Otherwise its what you^ are getting.
Lol, Okay.lol. still didnt get it.
dw, I guess I'll do it when my mind gets off of my phys exam tomorrow.
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