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Mathematics: Post your doubts here!

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http://papers.gceguide.com/A Levels/Mathematics (9709)/9709_s15_qp_22.pdf
Q1)(ii) I got least value as -21.6 and greastest as 21.6 so how n can be 43? :p
Q3(i) why tan theta cant be negative 4?
Q4(i) I got dy/dx = e^x - 8e^-2x. Now how to solve this when dy/dx = 0?
I did like this,
e^x(1 - 8e^-3x) = 0
ln (1/8) = -3x.
Then is it like, x = ln(1/8) / -3 ?
Q5(ii)(iii) No idea.
Thanks. :)
Anum96 See if u can help me. ^_^
Q3 (i) tan theta cant be negative because the qs says its an acute angle. tan 4 gives you 75.96 and since tan is negative in second and forth quadrant, your ans is 180 - 75.96 i.e. 104.04 which is in no way acute.
Q4 (i) dy/dx = e^x - 8e^-2x
Take e^x common
e^x(1 - 8e^-3x)=0
- 8e^-3x = - 1
e^-3x = 1/8
ln e^-3x = ln (1/8)
-3x lne = ln(1/8)
x = [ln(1/8)/-3)
x = 0.69314718 = ln2
Q5(ii) In these type of questions youre usually given with x1 value. If not just assume it to be 1
So put x equals 1 in the equation and keep solving like you solve other iterations. You will start getting 1.8038 consecutively and so this will be your answer. Rounding off will give you 1.804
(iii)Now use the ans to part (ii) for this part. Find the corresponding y value and that will be your answer. But remember there will be 2 answers since there are two intersecting points. One with positive x value and the other with negative :)
 
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Q3 (i) tan theta cant be negative because the qs says its an acute angle. tan 4 gives you 75.96 and since tan is negative in second and forth quadrant, your ans is 180 - 75.96 i.e. 104.04 which is in no way acute.
Q4 (i) dy/dx = e^x - 8e^-2x
Take e^x common
e^x(1 - 8e^-3x)=0
- 8e^-3x = - 1
e^-3x = 1/8
ln e^-3x = ln (1/8)
-3x lne = ln(1/8)
x = [ln(1/8)/-3)
x = 0.69314718 = ln2
Q5(ii) In these type of questions youre usually given with x1 value. If not just assume it to be 1
So put x equals 1 in the equation and keep solving like you solve other iterations. You will start getting 1.8038 consecutively and so this will be your answer. Rounding off will give you 1.804
(iii)Now use the ans to part (ii) for this part. Find the corresponding y value and that will be your answer. But remember there will be 2 answers since there are two intersecting points. One with positive x value and the other with negative :)
Thank you. Well I never solved questions for iterations before. Which chapter is this? :) Can u temme, so that I can refer to that chapter.. :) Thanks.. and so I didnt get the explanation f Q5. :)
I kept x =1 then 2 then 3, I got different answers. :/ Was I supoose to do this?? I never got 1.804 :(
What about Q1? :D
 
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Thank you. Well I never solved questions for iterations before. Which chapter is this? :) Can u temme, so that I can refer to that chapter.. :) Thanks.. and so I didnt get the explanation f Q5. :)
I kept x =1 then 2 then 3, I got different answers. :/ Was I supoose to do this?? I never got 1.804 :(
What about Q1? :D
Anum96 Also in Q6 how do we know we have to give answer in radian form?
 
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Anum96 Also in Q6 how do we know we have to give answer in radian form?
As for your question. Its better if you give your answer in both forms. I always gave two answers to be on the safe side. However, One things for sure. Whenever the question is in terms of pi, you're supposed to give it in radians.
 
Messages
455
Reaction score
7,676
Points
503
http://papers.gceguide.com/A Levels/Mathematics (9709)/9709_s15_qp_22.pdf
Q1)(ii) I got least value as -21.6 and greastest as 21.6 so how n can be 43? :p
Q3(i) why tan theta cant be negative 4?
Q4(i) I got dy/dx = e^x - 8e^-2x. Now how to solve this when dy/dx = 0?
I did like this,
e^x(1 - 8e^-3x) = 0
ln (1/8) = -3x.
Then is it like, x = ln(1/8) / -3 ?
Q5(ii)(iii) No idea.
Thanks. :)
Anum96 See if u can help me. ^_^
Why do u keep editing your messages? o_O I wouldn't have given you the same detail you know.
 
Messages
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273
Why do u keep editing your messages? o_O I wouldn't have given you the same detail you know.
Look, I edited that post so that u would have less to work... :)
I will get nothing to make u fall in trouble... :)

you know what i have also helped to so many ppl and if they did this, I never said this things... anyways sorry to trouble. :)
 
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