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Q3 (i) tan theta cant be negative because the qs says its an acute angle. tan 4 gives you 75.96 and since tan is negative in second and forth quadrant, your ans is 180 - 75.96 i.e. 104.04 which is in no way acute.http://papers.gceguide.com/A Levels/Mathematics (9709)/9709_s15_qp_22.pdf
Q1)(ii) I got least value as -21.6 and greastest as 21.6 so how n can be 43?
Q3(i) why tan theta cant be negative 4?
Q4(i) I got dy/dx = e^x - 8e^-2x. Now how to solve this when dy/dx = 0?
I did like this,
e^x(1 - 8e^-3x) = 0
ln (1/8) = -3x.
Then is it like, x = ln(1/8) / -3 ?
Q5(ii)(iii) No idea.
Thanks.
Anum96 See if u can help me. ^_^
Q4 (i) dy/dx = e^x - 8e^-2x
Take e^x common
e^x(1 - 8e^-3x)=0
- 8e^-3x = - 1
e^-3x = 1/8
ln e^-3x = ln (1/8)
-3x lne = ln(1/8)
x = [ln(1/8)/-3)
x = 0.69314718 = ln2
Q5(ii) In these type of questions youre usually given with x1 value. If not just assume it to be 1
So put x equals 1 in the equation and keep solving like you solve other iterations. You will start getting 1.8038 consecutively and so this will be your answer. Rounding off will give you 1.804
(iii)Now use the ans to part (ii) for this part. Find the corresponding y value and that will be your answer. But remember there will be 2 answers since there are two intersecting points. One with positive x value and the other with negative
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