Mathematics: Post your doubts here!

[Anum96]

Yep but not by that way ...

Okss

 

[nehaoscar]

Part iii ... which value do we use as the starting value for xn ??

 

[Anum96]

View attachment 58902
Part iii ... which value do we use as the starting value for xn ??

1
Btw where is that argument question u posted? Hogaya tha?

 

[nehaoscar]

1
Btw where is that argument question u posted? Hogaya tha?

Haan woh baad mein samaj aa gaya

 

[nehaoscar]

Ok so using the property a^2 = b^2
squaring both sides and solving a quadratic gives:
(3x-5)(x-1)<0
so 1<x<(5/3)
Then why not consider 1<x ... why only x<5/3 ??

 

[Rizwan Javed]

View attachment 58904
Ok so using the property a^2 = b^2
squaring both sides and solving a quadratic gives:
(3x-5)(x-1)<0
so 1<x<(5/3)
Then why not consider 1<x ... why only x<5/3 ??

The answers are :
x<5/3 and x<1

so we'll only consider x<5/3

 

[nehaoscar]

The answers are :
x<5/3 and x<1

so we'll only consider x<5/3

But then by the squaring method don't you draw a parabola and look for the answers between them...

Ignore the axis but like the red region would be the solutions .... so then why x<1

 

[Rizwan Javed]

But then by the squaring method don't you draw a parabola and look for the answers between them...
View attachment 58905
Ignore the axis but like the red region would be the solutions .... so then why x<1

Actually I don't know about that squaring rule.

I used the concept that that whenever a modulus is there, there are two possibilities,

either:

-(x-2) > 2x - 3

OR

(x-2) > 2x-3

So by solving these we get two two solutions that i mentioned above.

Is it from p3?

 

[nehaoscar]

Actually I don't know about that squaring rule.

I used the concept that that whenever a modulus is there, there are two possibilities,

either:

-(x-2) > 2x - 3

OR

(x-2) > 2x-3

So by solving these we get two two solutions that i mentioned above.

Is it from p3?

Yep

 

[Rizwan Javed]

Yep

okay.

 

[nehaoscar]

I'm getting xsin2t + ycos2t = acos4tsin2t + asin4tcos2t
Please can someone solve it so i can check what's wrong :/
And how to do this next part of the question too please ...

 

[Anum96]

View attachment 58906
I'm getting xsin2t + ycos2t = acos4tsin2t + asin4tcos2t
Please can someone solve it so i can check what's wrong :/
And how to do this next part of the question too please ...
View attachment 58907

You might want to gift me the whole questions, Nehaa

 

[nehaoscar]

You might want to gift me the whole questions, Nehaa

Sorryy!

 

[The Sarcastic Retard]

Sorryy!
View attachment 58908

(i) -tan^2(t) ?

 

[Anum96]

Sorryy!
View attachment 58908

There u go

 

[nehaoscar]

(i) -tan^2(t) ?

Yep

 

[nehaoscar]

There u go

Thanks! Oh so I just had to substitute the identity in the first part
Yay I get the second part now ^.^ thanks!

 

[Maayee]

can someone help me with this:
Helen has some black tiles, some white tiles and some grey tiles. She places a single row of 8 tiles above her washbasin. Each tile she places is equally likely to be black, white or grey. Find the probability that there are no tiles of the same colour next to each other.

the ans is 128/2187

 

[holoholo]

Calculation by vector product to find normal of plane OAB ?

 

[nehaoscar]

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https://www.xtremepapers.com/community/threads/maths-p3-summary.42747/
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