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Mathematics: Post your doubts here!

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Please explain part ii
I don't get it why to multiply by 7*6*5*4 .... and why not multiply further etc... :/
 
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The general rule is X ~ B ( n , p ) and p is the probability of success right...
Then the nos. divisible by 5 are 10,15 and 20
So shouldn't p be 3/12 = 0.25
But then how is it 0.2??
Please explain :S
 
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How to find k?
np = 96 and npq = 32
so p = 1/3
q = 2/3
n = 144
I don't know how to find k since no probability is given either ??
 
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View attachment 58802
How to find k?
np = 96 and npq = 32
so p = 1/3
q = 2/3
n = 144
I don't know how to find k since no probability is given either ??
For k, n = 9 (1,2,3,4,5,6,7,8,9) ; np <= k ; 9p = k ; 9(2/3) = k ; k = 6 Ans.
part 2 anyone please?
You got u (-2/5,11/5) right? Find its modulus. you get undrt(5). now Iz - uI = IuI will give you z-(2/5,-11.5) Plot that on your graph and make a circle with radius udrt(5). That's it :)
s12qp31 need help with q2 2nd part, can't get this right for some odd reason, anyone?
Just use your answer to part i. Take the product of your answer and 1 + 2x. combine the like terms and you will get the answer. :)
 
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I don't get it o_O
we found n as 144 but then we're using 9 here??
Which formula is it for the np<k ... np is the mean right?? ...
For k, n is 9. Since you have to find the probability of success. you just have to equate them. k/9 will be the probability and since you have p as 2/3
So, k/9 equals 2/3 ; 9(2/3) ; 6
Get it?
 
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Look. Probability of success here is what? 2/3 right?
Now, The question says that the random variable X is the number of these n integers less than or equal to k between 1 and 9 inclusive. How will you find the probability of success here? You need the value of k right? if k was lets suppose 4. You would just right the probability as 4/9. But you dont have k. So it will be k/9.
2/3 and k/9 are both probabilities of success so just equate them.
How about now? :)
 
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