Mathematics: Post your doubts here!

[osama ahmed ibrahim]

can i use claculator to find differentiation or intergration

 

[osama ahmed ibrahim]

i always find answers in pure MS as a mixed number
should i place all my answers as a mixed number
how to use calculator to covert fracton to mixed number

 

[The Sarcastic Retard]

can i use claculator to find differentiation or intergration

To check your answer yes you can as Fx - 991es plus is allowed.

 

[The Sarcastic Retard]

i always find answers in pure MS as a mixed number
should i place all my answers as a mixed number
how to use calculator to covert fracton to mixed number

Which calculator do u use?

 

[osama ahmed ibrahim]

Which calculator do u use?

casio fx-991es plus but how

 

[mistique_bee]

casio fx-991es plus but how

u will have a "S<=>D" button...when u get ur answer as mixed nmbr click shift and then click tht button..it will convert it into fraction

 

[areeba240]

how to solve the last two parts i.e. (b) and (c) of this qtn...plzzzzz helppppp
thanks in advance

 

[Rifat Fawzia]

so did you get the papers? because I do have two of them

no i didnt get !!!

 

[Sariya Khan]

View attachment 60291 plzz help the answer is 88.2

It can't be 88.2 cm! it's 33 cm.

 

[osama ahmed ibrahim]

can i use casio calculator to covert a degreee angle to radian

 

[osama ahmed ibrahim]

help in III AND IV

 

[osama ahmed ibrahim]

HELP IN II
HOW CAN I DO IT

 

[mistique_bee]

can i use casio calculator to covert a degreee angle to radian

yes u can ..just click on "shift" and then "mode"
option 3: Deg is degree
option 4: Rad is radians

 

[techgeek]

View attachment 60302 View attachment 60301
help in III AND IV

For (iii) we know the range of sin x is -1 to 1
-1 < sin x < 1
-3 <3 sin x <3
3 > -3sinx> -3
3+4 > 4 - 3 sinx > -3 +4
7 > 4-3sinx > 1

For (iv), you might know that only 1-1 function has inverse, i.e. the values of y at one certain point maps only to one value of x
When you sketch the graph, it would be apparent that 3/2 pi is the greatest value where the function could exist as one to one

 

[Saad the Paki]

View attachment 60304View attachment 60303
HELP IN II
HOW CAN I DO IT

1/2 pi = 90°
Tan (90-x) = sin (90-x)/cos (90-x)
But sin (90-x)= cosx and cos (90-x)= sinx
So tan (90-x) = cosx/sinx = 1/tan x = 1/k

 

[Saad the Paki]

In the graph should I use the boundaries as it is or do I have to make it 40.5. And when do we do this adding and subtracting of 0.5?
This what the er says "A large number of candidates plotted on an adjusted upper boundary, such as 39·5 or 40·5. "

 

[Sarosh Jameel]

kindly help with part 1 of this question.

 

[techgeek]

View attachment 60307 In the graph should I use the boundaries as it is or do I have to make it 40.5. And when do we do this adding and subtracting of 0.5?
This what the er says "A large number of candidates plotted on an adjusted upper boundary, such as 39·5 or 40·5. "

We only adjust the boundaries when there are gaps between boundaries. If the boundaries given were 1-40 then 41-50, you might see that data between 40-41 is not included. When we plot the graph, our line is continuous, (it isn't broken from 40-41 where data doesn't exist!), in order to make the data continuous, we create mid-boundaries, so that the lower range is up to 40.5 and the next range starts from 40.5. This kind of makes bridges between the data . In this scenario, x<50 includes ALL those which are less than 50, there is no restriction, so we just take the upper boundaries of each range only and plot accordingly.
For instance, see this graph:


They adjusted the boundaries here because the data given was broken in between. It was 21-24 for the first range and then 25-28, so they extended the lower range up to 24.5 and started the upper one from 24.5.

 

[mistique_bee]

 

[techgeek]

kindly help with part 1 of this question.

Collect the information given:

probability that children jump higher than 127 cm is 8/10 = 0.8

probability that children jump higher than 135 cm is 1/3= 0.333

Applying normal distribution as usual:

for 127 cm:

P (X> 127) = 1 - ϕ (127-μ) /σ

0.8 = 1 - ϕ (127-μ) /σ


for 135 cm:

P (X> 135) = 1 - ϕ (135-μ) /σ

0.333 = 1 - ϕ (135-μ) /σ


When you solve these two you end up with two equations:

μ=127 + 0.842σ

and μ=135 - 0.431 σ


Solving these two simultaneously:
you'll get
σ= 6.28

and

μ=132