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Mathematics: Post your doubts here!

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Was your answer to the first part y = 70e^[e^(-3t) - 1] ?

As t goes to infinity,
e^-3t tends to zero​
thus,
y tends to 70e^[0 - 1] = 70e^-1​

so we have:
yFinal = 70e^-1
yStart = 70 (from main question)

p = (yFinal/yStart)*100
p = 100e^-1​
Thanx alot!!
 
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IMG_20190106_013818.JPG

How are the values of α and β calculated in the last part? Anyone plz help.....
 
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in part (b)
For b (i), AC is the diameter of the circle so APC will be the angle opposite to the diameter, i.e. angle in a semicircle=90°
Or you can think of it by the other rule...ABCP is a quadrilateral with its vertices touching the circumference so opposite angles will be equal. Hence, angle APC=angle ABC

In b (ii), angle APB is subtended by the chord AB, whereas angle BPC by the chord BC.Angles subtended by chords of equal length are equal and since AB=BC, the stated angles are equal.

In b (iii) (a) APC=90 and APB and BPC are equal, so APB=90/2=45
In b(iii) (b), angle CPD is also subtended by an equal chord so it will also equal angle APB i.e. 45. Hence, APD= 45+45+45=135

For b(iv) see the diagram

IMG_20190106_171552.JPG
So angle PDC=90+8=98
 
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