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Re: Maths help available here!!! Stuck somewhere?? Ask here!
Ghalya001 said:This was a question i encountered in our Co-ordinate geometry class . I found the co-ordinates of one vertex but equating the equations by there's no way except the graph work i think this can be solved !! It might seem easy to you guys but its given me a hell already !! :x
The equations of two sides of a square are y = 3x - 1 and x + 3y -6 = 0. If ( 0, -1) is one vertex of the square find the coordinates of the other vertices.
:: Core Maths 3rd Edition; Pg 91, Q 11.
Answers = ( 9/10 , 17/10 ) <-- Found it !!
Other two can be
Either ( -18/10 , 26/10 ) and ( -27/10 , -19/10 )
Or ( 36/10 , 8/10 ) and ( 27/10, -19/10) !!