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Mathematics: Post your doubts here!

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Got it :) for the integral of 1/(a square+x square) the integral Wud b 1/a tan inverse of (x/a) +c
 
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i was just thinking of messaging you! could you please solve that integration question now? November 2011 paper 33 Q10
Still very difficult to show the solution here !
I have done the question, it is tricky but very easy.
 
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first, when they told you the tangent at point P passes through the origin and if you draw a straight line ..to find the gradient you will do
(y-0)/(x-0) and so you will the gradient for the tangent at P = y/x

then, from the dy/dx equation you got above, make it equal to y/x
so ..
e^-x (-x^2+2x) = y/x
and multiply the x.. you will end up with y= e^-x (2x^2-x^3) ..this is your y!
substitute this y in the equation y=x^2e^-x to get
x^2e^-x = e^-x(2x^2 - x^3)
cancel the e^-x

you will get
x^2 = 2x^2 - x^3
-1x^2 = -1x
-1x=-1
so x=1 :D
 
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can anybody post the link or something for any notes of vectors? please that would be great help cause i dont know anything about them !
 
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I didn't make these, all thanks goes to the members here
 

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