is there any book or site where i can get the concept of this formula ? thanks,by the wayMean= Σ(x − a)/n +a
where a is a constant
Variance Σ(x − 25)^2 / n - [mean]^2
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is there any book or site where i can get the concept of this formula ? thanks,by the wayMean= Σ(x − a)/n +a
where a is a constant
Variance Σ(x − 25)^2 / n - [mean]^2
i didnt get it right... in MS how in the world did they get Z=1.882..yes.
hey check this question out.. in part 2 u do 4!/2! right? how to solve part 1 using this factorial method? it gets me confused when to use the factorials and when to use nPr.. :/Well that's a surprising question. Student, though.
I am not so sure, :/ do u Live in Khobar/Dammam?is there any book or site where i can get the concept of this formula ? thanks,by the way
thanks dude :]alright here you go
i)When ever you have to find the original mean=E(x-a)/n +a
so here the mean is given as 28.325. Find the value of n from the equation by substituting the value of E(x-a). 28.325-a=E(x-a)/n where a=25 n=40
For the s.d you should remember that s.d isnt affected by constant shifts in the data such as -a.
assume that x-a =y so E(x-a)=E and hence E(x-a)^2=E^2
s.d=underoot(E^2/n-(E/n)^2)
s.d=9.11
ii)check your data booklet one of the formula for s.d is underoot(E(x)^2/n - (E(x)/n)^2). Since you know that the s.d is 9.11 and that the original mean is 28.325 substitute the given values and find the value of (E(x)/n )^2.
yes the cambridge s1 book by steve dobbsis there any book or site where i can get the concept of this formula ? thanks,by the way
hahaI used the alphabet y which is in brackets ()where u see the thumbs up icon
6C4 * 4!. Or it can be 6P4. If orders are important (prizes in some cases0 , Permutation is to be used. If not (order does not matter, example choosing people for commitee,etc)hey check this question out.. in part 2 u do 4!/2! right? how to solve part 1 using this factorial method? it gets me confused when to use the factorials and when to use nPr.. :/
u have to inter-connect the intervals. First Interval: 1-100, 101-150.Please help me in the last part? how to calculate mid values?
please explain the 4th and 5th part of the same questionn.. :/6C4 * 4!. Or it can be 6P4. If orders are important (prizes in some cases0 , Permutation is to be used. If not (order does not matter, example choosing people for commitee,etc)
In this question. order is important
i have the exact same doubt.. hope somone clears it up!No.4 http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s05_qp_6.pdf
What is the accepted way by CIE to find the upper and lower quartile with an even number of terms?
i got 5.4 for LQ and UQ 8.35 according to my teacher's method...but the marking scheme showed 8.3 and 5.4
dude if the total frequency is odd like 21 .. to find the median u add 1 to it and divide by 2. 21+1/2 so its the 11th value.i wanted to know when to take the mean of the data when calculating the quartiles.for eg. in M/J/2010 paper 61 stats,in question 2, we get the following steam-and-leaf diagram.0|2 5 6 8 8 (5)1|2 4 6 7 7 9 (6)2|1 2 3 3 3 5 6 7 (8)3|1 5 (2)now in calculating the median, we will divide the total number of data by 2 which in this case is21/2=10.5 so, which value will we take? 10 th value or 11thvalue or the mean of the 10th and 11th value.also in calculating the lower quartile, we get 21/4=5.25 here also, do we take the 5th value or the 6th value or the mean of the 5t and 6th value?again in calculating the upper quartile, we get 21*0.75=15.75 here again do we take the 15th value or the 16th value or the mean of the 15th and 16th value?sometimes in the mark scheme i have seen them taking the mean and sometimes the value immediately next to it.. im confused as to what should i do?WILL appreciate any help!tomorow is the exam please help!
I think u have to take (n+1)/2i wanted to know when to take the mean of the data when calculating the quartiles.for eg. in M/J/2010 paper 61 stats,in question 2, we get the following steam-and-leaf diagram.0|2 5 6 8 8 (5)1|2 4 6 7 7 9 (6)2|1 2 3 3 3 5 6 7 (8)3|1 5 (2)now in calculating the median, we will divide the total number of data by 2 which in this case is21/2=10.5 so, which value will we take? 10 th value or 11thvalue or the mean of the 10th and 11th value.also in calculating the lower quartile, we get 21/4=5.25 here also, do we take the 5th value or the 6th value or the mean of the 5t and 6th value?again in calculating the upper quartile, we get 21*0.75=15.75 here again do we take the 15th value or the 16th value or the mean of the 15th and 16th value?sometimes in the mark scheme i have seen them taking the mean and sometimes the value immediately next to it.. im confused as to what should i do?WILL appreciate any help!tomorow is the exam please help!
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