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These are last year's GT for A*. (2nd page)guys if ive got 74 in p1 46 in m1 68 in p3 how much would i need in s1 to get an A* . Grade threshold for A in s1 is between 33 and 38
weren't they supposed to be greater than 5 , not 20?np or nq > 20 then u find the probability using normal otherwise binomial.
oh wow thanks. didnt knw there was a second page to it Insha Allah we all get A*These are last year's GT for A*. (2nd page)
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_gt.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_gt.pdf
Atm ur total is 188, u need around 35 to make it happen. But it depends if the session's paper easier or harder than last year's?
oh wow thanks. didnt knw there was a second page to it Insha Allah we all get A*
oh yea sorry 5weren't they supposed to be greater than 5 , not 20?
weren't they supposed to be greater than 5 , not 20?
get 50 then ul get a distinction try your bestIm hoping too. I hope 75,75,50 in p1,p3 and p4. im worried about p6 now
yeah I know thatThats for checking whether you can possibly transform a binomial distribution to a normal distribution.
If A ~ B (n,p) then A ~ N (np, npq); where np > 5 and npq > 5
its np and nq >5 not npqThat's for checking whether you can possibly transform a binomial distribution to a normal distribution.
If A ~ B (n,p) then A ~ N (np, npq); where np > 5 and npq > 5
Pray for me mate. p6 is scaring me more than p3get 50 then ul get a distinction try your best
please anser my questionnnni dint get u ..........i was asking sth different Khan_971
its np and nq >5 not npq
u get thee total arrangement with no restrictions, then if for example u need to separate 2 persons , then u get the number of arrangements when they r together and subtract it from the total.how do you arrange the ppl who must be seperated from each other without using the method of all possible ways minus the ways that they sit together?
is there any other method?? help!!! i'm very weak in permutation and combination!!!
for example there are 7 people and two must be seperated. so its like *p*p*p*p*p* where p refers to the 5 people who are and * are the possible places for those who dont want to sit together. therefore 5! *6P2how do you arrange the ppl who must be seperated from each other without using the method of all possible ways minus the ways that they sit together?
is there any other method?? help!!! i'm very weak in permutation and combination!!!
but please check june 11 63 question 5)iii) they said normal distribution but in the ms they said with or without cc, can u see this and make it clearer to me??CC is only in normal approximation :/
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