Mathematics: Post your doubts here!

[mukki]

weren't they supposed to be greater than 5 , not 20?

oh yea sorry 5

 

[Aarjit]

weren't they supposed to be greater than 5 , not 20?

That's for checking whether you can possibly transform a binomial distribution to a normal distribution.

If A ~ B (n,p) then A ~ N (np, npq); where np > 5 and nq > 5

 

[mukki]

Im hoping too. I hope 75,75,50 in p1,p3 and p4. im worried about p6 now

get 50 then ul get a distinction try your best

 

[sea_princess]

Thats for checking whether you can possibly transform a binomial distribution to a normal distribution.

If A ~ B (n,p) then A ~ N (np, npq); where np > 5 and npq > 5

yeah I know that

 

[mukki]

That's for checking whether you can possibly transform a binomial distribution to a normal distribution.

If A ~ B (n,p) then A ~ N (np, npq); where np > 5 and npq > 5

its np and nq >5 not npq

 

[Khan_971]

get 50 then ul get a distinction try your best

Pray for me mate. p6 is scaring me more than p3

 

[hassam]

i dint get u ..........i was asking sth different Khan_971

please anser my questionnnn

 

[Ashleyxoxo93]

how do you arrange the ppl who must be seperated from each other without using the method of all possible ways minus the ways that they sit together?
is there any other method?? help!!! i'm very weak in permutation and combination!!!

 

[Aarjit]

its np and nq >5 not npq

Agreed. Got carried away.. Statistics overdose!

 

[sea_princess]

how do you arrange the ppl who must be seperated from each other without using the method of all possible ways minus the ways that they sit together?
is there any other method?? help!!! i'm very weak in permutation and combination!!!

u get thee total arrangement with no restrictions, then if for example u need to separate 2 persons , then u get the number of arrangements when they r together and subtract it from the total.

 

[starlight123]

can nybdy pls solve q6 b part 1 n 2
and q7 part 3
http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_61.pdf

 

[mukki]

how do you arrange the ppl who must be seperated from each other without using the method of all possible ways minus the ways that they sit together?
is there any other method?? help!!! i'm very weak in permutation and combination!!!

for example there are 7 people and two must be seperated. so its like *p*p*p*p*p* where p refers to the 5 people who are and * are the possible places for those who dont want to sit together. therefore 5! *6P2

 

[shan5674]

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w09_qp_62.pdf

1(ii)? please?

 

[omar hazem]

CC is only in normal approximation :/

but please check june 11 63 question 5)iii) they said normal distribution but in the ms they said with or without cc, can u see this and make it clearer to me??

 

[Ashleyxoxo93]

ok thank you so much!!! u guys r genius ))

 

[Wanzi21]

how to do this? last question is always the hardest of all!!!

 

[Khan_971]

but please check june 11 63 question 5)iii) they said normal distribution but in the ms they said with or without cc, can u see this and make it clearer to me??

i dont know

 

[Ashleyxoxo93]

for approximation questions, when do you +0.5 and when do you -0.5? im always confused with this. e.g using a suitable approximation, find the probability that more than 155 people wore a watch on their left wrist. what if they asked for less than 155? or at least? or at most?

 

[hassam]

weelll for green gage one.....i was doing lykk this that....figured out when twoGS are 2gether....not exactly two...meany two and three both are there.....so got 8!/3!......and then wanted to subtract form when there were 3 Gs 2gether that is 7!/3!.......bt ms says 2* 7!/3!...plxx smbody tell me what i m overcounting @Khan_97171 plx anser thisss

 

[omar hazem]

i dont know

ok i hope it won't come confusing problem in our exam tomorrow :/