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Mathematics: Post your doubts here!

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Well, this was how I'd solved it before:

Simply 'choose' 2 Gs out of 3, and the remaining 7 letters can be completely random!

G G _ _ _ _ _ _ _...............[consider GG to be 'attached' together so that it can alternate in 2! ways]

n = 2! x 3c2 x 7!.................. [but don't forget that there are 3 recurring Es too!]
..............3!
...= 5040...... Q.E.D


P.S. If you're still uncertain, let me know. I'll work in it one more time.
CNT GET UR WAYYY,,,,,,,,my stratergy was too find two Gs 2gether,,,,,,without emphaisizing exctly 2 meaning i ll have calculated both 2 and 3 and then subtract that from exactly 3....bt dount knw where's the problem
 
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help???

thanks in advance
 

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Since probability of going to park is 0.6,hence not going is 0.4. The dog barks when goes to park = 0.6x 0.35 aand not going to park = 0.4x0.75.Sum it up =)
sorrY bt have askd fr the last part :eek: any ways thanx fr ur co-operation i gt ma answer
 
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this question has been solved three to 4 times plz check from pages 170 onwards
i know how to solve this i was just wondering when should we use this method and when do we just use the probability they've given?
 
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i know how to solve this i was just wondering when should we use this method and when do we just use the probability they've given?

the probability given will be still using it.. and when they say "within", we hv to find the lower and upper boundary.
 
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please in june 11 63 S1 question 5)iii), i need to know why they used CONTINUITY CORRECTION in the mark scheme although there was no term in the question indicating this like normal approximation or suitable approximation??
please answer soon to help me and others :)
 
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