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Mathematics: Post your doubts here!

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yes the answer is the same but i want to know the method

is like this:

s = (1/6)gt^2 (given from question)
s = ut+(1/2)at^2 (what we normally know)
since it start at rest, therefore u=0,

s = (1/2)at^2 , compare with the given s = (1/6)gt^2,
we will find that a = g/3

then the force acting on the box is:
mg-R=ma
R=mg-ma
R = mg - m(g/3)
R = (2mg)/3
 
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hey i hve just started as- level....can anyone pls solve question 4B miscellenous excercise from the P1 book??? asap
 
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Hey guys can someone please help me in this question from the (ii) part onwards :unsure:
 

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Can someone please give me the name of the standard Mathematics book for A Level...
& is it possible to study for A level maths at home...
I did IGCSE maths at home & got an A* & I really felt comfortable at home :)
 
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The diagram, not drawn to scale, shows a trapezium OABC with OA parallel to CB.
Given that B is the point (4, 3), C is the point (0, 2) and the diagonal CA is parallel to
the xaxis, calculate the coordinates of A.
 
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The diagram, not drawn to scale, shows a trapezium OABC with OA parallel to CB.
Given that B is the point (4, 3), C is the point (0, 2) and the diagonal CA is parallel to
the xaxis, calculate the coordinates of A.

can you post the picture of the diagram? it will be much easier to understand the question that way :)
 
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Need help in using the quadrant thing.How to use in trigonometric questions? Any notes on it? JazakAllah

For Reference:

newcast.gif
 
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Aoa wr wb
i need some help in this qn: integral of [(x*n) (lnx)]
limits are : 'e' and '1'
Please need help urgently with this qn
Jazakallah!

PS: A2 level qn
 
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Aoa wr wb
i need some help in this qn: integral of [(x*n) (lnx)]
limits are : 'e' and '1'
Please need help urgently with this qn
Jazakallah!

PS: A2 level qn
save this image in ur computer and then zoom it!!!it will help!!
Jay shree krishna!!:)
 

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not pastpapers , it's from my teacher's notes .

easy,
since CA is parallel to x-axis,
then we will know that y-coordinate for A is 2.

then in order for OABC to be a trapezium,
CB must be parallel to OA,
just let
gradient BC = gradient OA,
then you will be able to find the coordinates for A.
 
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