• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

Messages
869
Reaction score
374
Points
73
Good afternoon ,
can anyone help me in question 7 part ii & iii may/june 2006
here's the link
it's urgent .
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_4.pdf
7 ii) they r moving on a smooth plane so a = g sinθ and the height is 1.6m and the distance moved is d = 2.6t so d = 2.6(2.5) which is 6.5m
now we need to find sinθ which is the height ( opposite ) / hypotenuse which is the distance moved so sinθ = 16/6.5
a = 10( 16/6.5)
a= 2.46 ms/2

7 iii) when q is at the highest point it means its final velocity is equal to zero so..
v = u + at
0 = -1.3 + 2.46t
t = 0.528s

now find the distance moved by particle p by substituting the t = 0.528 in the equation s = ut+ 1/2 at^2

i hope this helped u!
 
Messages
66
Reaction score
110
Points
43
Plz someone help me with this one :(
A line joining a vertex of a triangle to the mid-point of the opposite side is called a median. Find the length of the median AM in the triangle A(-1,1), B(0,3) and C(4,7).

Nd

A line has vertices A(-2,1), B(3,-4) and C(5,7).
(a) Find the coordinates of M, the midpoint of AB, and N midpoint of AC.
(b) Show that MN is parallel to BC

Can someone plz tel me hw to do part (b)

And

The points A(2,1), B(2,7) and C(-4,-1) form a triangle. M is the midpoint of AB and N is the midpoint of AC.
(a) Find the lengths of of MN and BC.
(b) Show that BC=2MN.
Only part (b)

Thnx in advance :)
 
Messages
1,882
Reaction score
1,331
Points
173
Taiyaba

Q.1. A line joining a vertex of a triangle to the mid-point of the opposite side is called a median. Find the length of the median AM in the triangle A(-1,1), B(0,3) and C(4,7). The situation depicts M as the midpoint of BC so first find that one. After you have the coordinates of the midpoint, go ahead applying the length/magnitude formula for coordinates of A and M to find te length of the median.

Q.2.A line has vertices A(-2,1), B(3,-4) and C(5,7).
(a) Find the coordinates of M, the midpoint of AB, and N midpoint of AC.
(b) Show that MN is parallel to BC
Can someone plz tel me hw to do part (b)
For parallel lines, the gradient is same, that is, m1=m2. So find the gradients of both MN and BC. If they're equal, then you've proven that the lines are parallel.

Q.3.The points A(2,1), B(2,7) and C(-4,-1) form a triangle. M is the midpoint of AB and N is the midpoint of AC.
(a) Find the lengths of of MN and BC.
(b) Show that BC=2MN.
Only part (b)
Find the lengths of both BC and MN using the length formula. The length of BC must be twice that of MN(e.g. if BC is 10, MN is 5).
 
Messages
66
Reaction score
110
Points
43
Taiyaba

Q.1. A line joining a vertex of a triangle to the mid-point of the opposite side is called a median. Find the length of the median AM in the triangle A(-1,1), B(0,3) and C(4,7). The situation depicts M as the midpoint of BC so first find that one. After you have the coordinates of the midpoint, go ahead applying the length/magnitude formula for coordinates of A and M to find te length of the median.

Q.2.A line has vertices A(-2,1), B(3,-4) and C(5,7).
(a) Find the coordinates of M, the midpoint of AB, and N midpoint of AC.
(b) Show that MN is parallel to BC
Can someone plz tel me hw to do part (b)
For parallel lines, the gradient is same, that is, m1=m2. So find the gradients of both MN and BC. If they're equal, then you've proven that the lines are parallel.

Q.3.The points A(2,1), B(2,7) and C(-4,-1) form a triangle. M is the midpoint of AB and N is the midpoint of AC.
(a) Find the lengths of of MN and BC.
(b) Show that BC=2MN.
Only part (b)
Find the lengths of both BC and MN using the length formula. The length of BC must be twice that of MN(e.g. if BC is 10, MN is 5).
Thnk u thnk u thnk u sooooooo mch :D :p
 
Messages
7
Reaction score
0
Points
11
I need help in this question as soon as possible, I've a test, and I looked through out all the years and i didn't find it.
can any one help me please ?:(Capture.PNG
 
Messages
33
Reaction score
7
Points
18
Hey guys!
I would be grateful if someone can please help me with this question.
kindle sketch the graph!
its taken from Oct/Nov 2011
3 (i) Sketch, on a single diagram, the graphs of y = cos 2q and y = 1
2 for 0 ≤ q ≤ 2p. [3]
(ii) Write down the number of roots of the equation 2 cos 2q − 1 = 0 in the interval 0 ≤ q ≤ 2p. [1]
(iii) Deduce the number of roots of the equation 2 cos 2q − 1 = 0 in the interval 10p ≤ q ≤ 20p. [1]

Many thanks
 
Messages
330
Reaction score
191
Points
53
Hey guys!
I would be grateful if someone can please help me with this question.
kindle sketch the graph!
its taken from Oct/Nov 2011
3 (i) Sketch, on a single diagram, the graphs of y = cos 2q and y = 1
2 for 0 ≤ q ≤ 2p. [3]
(ii) Write down the number of roots of the equation 2 cos 2q − 1 = 0 in the interval 0 ≤ q ≤ 2p. [1]
(iii) Deduce the number of roots of the equation 2 cos 2q − 1 = 0 in the interval 10p ≤ q ≤ 20p. [1]

doc.png
 
Top