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You may wish to refer to this which I previously solved for someone else:
Thanks Buddywell i think no
See bro substitute value of 5/3 and then u get 0.33333333 left hand side and -0.333333 on the right hand side which means that 0.33333 is not less than - 0.333333 and so it's false....and we done take it though confirm with whitecorpView attachment 16393
For this question I get two critical values x=1 or x=5/3. But in the mark scheme they only consider x=1. Why??? Plz whitecorp or anyone help me.
See bro substitute value of 5/3 and then u get 0.33333333 left hand side and -0.333333 on the right hand side which means that 0.33333 is not less than - 0.333333 and so it's false....and we done take it though confirm with whitecorp
Ya bro so tried any vectors sums..thnx ya it makes sense.
A ball is thrown vertically upward and is caught at the same height 3 seconds later. Find (a) the distance it rose (b) the speed with which it was thrown .
can someone please help me with some unit vector questions? I totally forgot how to do them again.
The vector A has x and y and z-components of 8, 12, and -4 units . (a) Write the
vector equation of this vector in terms of the unit vectors i,j, and k. (b) find the unit
vector of a vector B one forth the length of A pointing in the same direction as A.
i did part (a) i am stuck on (b)
thanks
Hi. Can anyone solve this question for me . Iwould be grateful.
(i)Prove The Identity cos4x + 4cos2x = 8(cosx)^2 -3
(ii) Hence solve the equations for 0<x<360.
plz solve it with detail showing every important step. Thanks in advance.
Thanks a millioon , Helped me a loootThere is symmetry involved here-the path of the ball on the way upwards, and that of the ball on the way downwards.
Let initial velocity of the ball be u, then time taken to travel upwards =3/2 =1.5s
When it attains its maximum height before falling downwards, velocity =0
Hence, 0= u + (-g)(1.5) =======> u=1.5g m/s (shown)
(Note that I have assigned upwards as being positive for the first half of the journey, therefore acceleration due to free fall aka g is defined in the negative sense.)
Also, 0^2 = u^2 -2(g)(s)
Substituting in (1): 0=2.25g^2 - 2g(s)
Solving gives s = 2.25/2 =1.125 g metres. (shown)
(Not sure if you use g =9.81 or 10 m/s^2, so I will leave it to you to stick in the appropriate value for both answers)
Hope this helps. Peace.
Thanks a millioon , Helped me a looot
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