• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

Messages
222
Reaction score
25
Points
38
Hello, I need help on the last part of this question.

I got the equation like in the mark scheme but how do you get x approaches 10 for the last part?

Thanks Capture2.PNGCapture.PNG
 

Attachments

  • Capture2.PNG
    Capture2.PNG
    54.8 KB · Views: 4
  • Capture.PNG
    Capture.PNG
    12.2 KB · Views: 7
Messages
16
Reaction score
3
Points
13
Hi can anyone help me in ths question. I dnt know what to do in the second part.

Question is : the parametric equation of a curve are x=2cost , y=5+3cos2t , where 0<t<pie .
Express dy by dx in terms of t, and hence show that the gradient at any point of the curve is less than 6.
 
Messages
164
Reaction score
111
Points
43
Hi can anyone help me in ths question. I dnt know what to do in the second part.

Question is : the parametric equation of a curve are x=2cost , y=5+3cos2t , where 0<t<pie .
Express dy by dx in terms of t, and hence show that the gradient at any point of the curve is less than 6.

dy/dt = -6sin2t, dx/dt= -2sint

dy/dx = dy/dt divided by dx/dt = -6sin2t/-2sint = 3sin2t /sin t =3 (2sint cost)/sin t = 6 cost
Since 0<t<pi, -6 <6cost <6 (shown)
Note that dy/dx denotes the gradient function of the curve at a generic point for a parameter value of t.

Hope this helps. Peace.
 
Messages
164
Reaction score
111
Points
43
I am reposting this.. is anyone willing to help me?? :(

8KlqC.jpg


The diagram shows the graph of y = x^n, where n is an integer. Given that the curve passes between the points (2, 200) and (2, 2000), determine the value of n.

Please explain the solution step-by-step.. thanks!

What exactly do you mean by passing between the points? Does the curve pass through those two given points?

If it does, you may wish to check if you have provided the correct set of coordinates. It is obvious the graph is strictly increasing but yet your two points have the same x-values (which means the strictly increasing nature of the graph automatically breaks down).

Peace.
 
Top