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Mathematics: Post your doubts here!

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ya dy/dx is -tant which I got it the question is the second part in which i have to find the equation of the tangent help me in that plz and then the third or last part plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz workings plz
and hey bro if possible attach a scan
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look here found a TECHINIQUEx


sin^2x = (1- cos2x)/2 ratio of x on both sides is of 1: 2

now if it becomes.... sin^2(2x) then make sure the ratio is the same


i.e sin^2(2x) = (1-cos4x)/2

integrate it now 1/2x - sin4x/8

:)
 
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parthrocks


sin^2x = (1- cos2x)/2 ratio of x on both sides is of 1: 2

now if it becomes.... sin^2(2x) then make sure the ratio is the same


i.e sin^2(2x) = (1-cos4x)/2

integrate it now 1/2x - sin4x/8
Dude the main part that i have a doubt is in third one how to integrate its getting complicated when i use the product rule
showme steps
 
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