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The volume ,V cm^3 of a sphere of a radius r cm,is given by the fromula V=4/3 pie r^3. A pump put air into a second spherical baloon at the rate of 1200 cm^3/s.Calculate the rate in cm/s, at which the radius is increasing at the instant when radius is 5 cm?
I hope someone will solve this
dV/dr = 3* 4/3π r^2 dV/dt= 1200 cm^3/s
= 4πr^2
dr/dt = dr/dV * dV/dt
dr/dt = [1/(4πr^2)] * 1200
substitute r=5
dr/dt = [1/(4π *25)] *1200
dr/dt =3.82 cm/s