Mathematics: Post your doubts here!

[VelaneDeBeaute]

this is how i did it
(i)let PN= y
the triangle PTN is equal to tanx so
0.5x(y x TN)= tanx
TN=2tanx/y
dy/dx = y/ (2tanx/y)
=y x y/2(sinx/cosx)
=y^2 x 1/2(cosx/sinx)
=1/2 y^2 cotx

(ii) dy/dx =y^2/2 x cosx/sinx
2/y^2 dy= cosx/sinx dx (integrate this)
-2y^-1 =ln(sinx) +c
apply y=2 x=1/6 pi
c=-1-ln(1/2)
put it in the equation and get y=2/(1-ln2sinx)

hope you get it

Thank you so much. I was missing just a spot and the whole question seemed to go wrong.

 

[VelaneDeBeaute]

Anybody knows where I can revise Complex Numbers for Paper 3?

 

[iKhaled]

Anybody knows where I can revise Complex Numbers for Paper 3?

2nd worst chapter after vectors i hate them

 

[Rutzaba]

2nd worst chapter after vectors i hate them

i love vectors

 

[Rutzaba]

wen i had pobs wth complex numbers i was like sir pleeze?
sir called us on a sunday at 8 am in the morning ,,, at ten thirty wen we left th room... we knerw it by heart

though afta 8 months of no practice i hardly remember!

 

[Maz]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_13.pdf

umm guys question 3 please?

1) Open the brackets.
(1-4x+4x^2) (1+6ax+15a^2 x^2...) [you don't need anymore since we want the first three terms]
2) The first term we already have 1
Second term- find all the combinations between the brackets that will give us "-x"
(4x*1)+(1*6ax) = -x [divide both sides by 'x']
4+6a= -1
a=1/2
3) The third term- find all the combinations between the brackets that will give us "bx^2"
(4x^2*1)+(-4x*6ax)+(1*15a^2 x^2)= bx^2
4x^2 - 24 ax^2 + 15 a^2 x^2 = bx^2 [divide both sides by x^2)
4 - 24a +15a^2 = b [put the value of 'a' in]
b = -41/2

I'm not sure whether i have explained it in a proper manner, if you still have a doubt i'll try to explain it in another way

 

[Esme]

wen i had pobs wth complex numbers i was like sir pleeze?
sir called us on a sunday at 8 am in the morning ,,, at ten thirty wen we left th room... we knerw it by heart

though afta 8 months of no practice i hardly remember!

He must have been an amazing teacher!!

 

[yubakkk]

PLEASE HELP THIS QUESTION
A manufacture of biscuits produces 3 times as many cream one as chocolate one.Biscuits are chosen randomly and packed into boxes of 10.Find the probability that a box contain equal number of cream and chocolate biscuit.

 

[abruzzi]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_61.pdf
Someone please help me solve question no. 6 - the whole question. I'll appreciate an explanation..

Thanks

 

[sma786]

Hey,
i wanted some good notes for my paper 1 and paper 6 because i'm done with revision and past papers from 2003-2011
but still i need to revise, so please

 

[falcon678]

1) Open the brackets.
(1-4x+4x^2) (1+6ax+15a^2 x^2...) [you don't need anymore since we want the first three terms]
2) The first term we already have 1
Second term- find all the combinations between the brackets that will give us "-x"
(4x*1)+(1*6ax) = -x [divide both sides by 'x']
4+6a= -1
a=1/2
3) The third term- find all the combinations between the brackets that will give us "bx^2"
(4x^2*1)+(-4x*6ax)+(1*15a^2 x^2)= bx^2
4x^2 - 24 ax^2 + 15 a^2 x^2 = bx^2 [divide both sides by x^2)
4 - 24a +15a^2 = b [put the value of 'a' in]
b = -41/2

I'm not sure whether i have explained it in a proper manner, if you still have a doubt i'll try to explain it in another way

dude how bout tht anthr way....m still kinda confused here....

 

[syed1995]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_61.pdf
Someone please help me solve question no. 6 - the whole question. I'll appreciate an explanation..

Thanks

Probability she is on time = p = 1-0.75-0.05
p= 0.2
q= 1-0.2 = 0.8
n=96

We will be using normal approximation to solve this question...

Using Normal Approximation To Binomial

mean = np = 96*0.2 = 19.2
SD = √npq = √96*0.2*0.8 = √15.36

P(X<20)
Continuity Correction P(X<19.5)
P(z<[19.5-19.2]/√15.36)
P(z<0.07654)
Check the value of z from the normal distribution table.
= 0.531


ii)
She eats a banana if early = 0.7
She doesn't eat if early = 0.3
She eats a banana if on time = 0.4
She doesn't eat if on time = 0.6
She doesn't eat a banana if late = 1

probability she is late and doesn't eat a banana = 0.75*1 = L-B'
probability she is on time and doesn't eat a banana = 0.2*0.6 = OT-B'
probability she is early and doesn't eat a banana = 0.05*0.3 E-B'


(Given She Doesn't Eat A Banana| She Is On Time) (B'|E)

It means that all conditions of (her not eating a banana) will go in the denominator while (her being on time and not eating the banana) will go in the numerator

OT-B'/(L-B' + E-B' + OT-B')

(0.2*0.6)/[(0.75*1) + (0.05*0.3) + (0.2*0.6)]

= 8/59 Answer

 

[PhyZac]

PLEASE HELP THIS QUESTION
A manufacture of biscuits produces 3 times as many cream one as chocolate one.Biscuits are chosen randomly and packed into boxes of 10.Find the probability that a box contain equal number of cream and chocolate biscuit.

There are total 10 biscuits, and equal number means, 5 cream and chocolate.
Probability cream is 3/4 [ because ratio is 3:1 ]
and Probability not cream (that is chocolate) is 1/4

now to get 5 cream we use binomial distribution method.

10C5 x (3/4)^5 x (1/4)^5 = 0.0584

 

[Shreeram]

can anybody help me with quest 6 ii. Im stuck. Thanks

 

[dana xP]

i need some p4 revision notes plz ..... am really stuck in mechanics especially in work.energy,power thingy :'(

 

[Safraz]

Anyone have some helpful notes for p5 (mech 2)? Especially for the equilibrium topics and maybe elastic spring and strings

 

[Shreeram]

can u help me with quest 6 ii june 12 p41

 

[Safraz]

can u help me with quest 6 ii june 12 p41

Hopefully this helps

 

[Shreeram]

check this site http://www.examsolutions.net/maths-revision/syllabuses/CIE/period-1/M2/module.php
I hope this would help u understand.

 

[unseen95]

please help me with question number 10(b) in detail. Link to the question is http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_31.pdf