- Messages
- 1,601
- Reaction score
- 553
- Points
- 123
thank you very very very muchCheck the first link again. There is no part 4...
w05 qp 3
Q7 iii
Mark a point at (1, 2).
|z| = |z - 1 - 2i|
|z - (0 + 0i)| = |z - (1 + 2i)|
Construct a perpendicular bisector of (0, 0) and (1, 2).
----------------------------
w04 qp 3
Q9 iii
Put Q in m:
<2, 0, -1> = <-2, 2, 1> +t<-2, 1, 1>
From one equation, you get t = -2. Test the remaining two equations with this value. It should satisfy them.
PQ = <-2, -1, -3> (By putting s = 2)
Make a dot product with 'm' and see if the answer is zero.
-----------------------
w04 qp 3
Q10
i)
V = 1000h
dV/dh = 1000
dV/dt = 30 - k√h
dh/dt = dh/dV x dV/dt
dh/dt = (1/1000) (30 - k√h)
When h = 1, dh/dt = 0.02
0.02 = (1/1000) (30 - k)
k = 10
dh/dt = 0.01(3 - √h)
ii)
[(x - 3)/x] dx = 0.005 dt
(1 - 3/x) dx = 0.005 dt
x - 3ln|x| = 0.005t + c
When x = 3, t = 0
3 - 3ln3 = c
x - 3ln|x| = 0.005t + 3 - 3ln3
0.005t = x - 3 - 3ln|x| + 3ln3
t = 200(x - 3 + 3ln|3/x|)
iii)
x = 3 - √h
x = 3 - √4 = 1
t = 200(1 - 3 + 3ln|3/1|) = 259
i get it now
oh yeah sorry
i meant part 2