We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Honestly for P1 1hr 45 is plenty.naw.. I was talking about physics and chemistry.. they are 1 hour each for theory.. It takes 1 hour to solve them.. so one can solve like 3 or 4 papers in a day.. but with maths P1 I can't even solve 2 papers a day :\
And no one can solve the paper in 45 minutes! .. takes me about 1hr 30-40 minutes to solve a complete paper..
Wait, you mean phi of statistic.PhyZac or anyone else..
Know of any place (online or via calculator) where one can get inverse of phi? without referring to the normal tables I mean...
there is a calculator function but i tried but didnt knoe its use properlyPhyZac or anyone else..
Know of any place (online or via calculator) where one can get inverse of phi? without referring to the normal tables I mean...
thanks man that really helped!Okay, from first part you get that dy/dx = -sint/cost
Now they want the equation of tangent when t is t!!
Equation is in form
(y-y1) = m (x-x1)
M is the gradient, and when t is t, the gradient is -sint/cost ( the dy/dx)
the y1 is asin^3 (t)
and the x1 is acos^3(t)
Sub those value, and do some algebra and then you get the answer! [P.S, i am sure you know how to do this step, if you get any difficulty ask]
OKaay..see..!http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_31.pdf
Please help for no. 7 (i)
OKaay..see..!
First we will do the limits.
in the first one it is 2 and 0
so, the sub is x = t^2 + 1
when t is 2, x is 5
when t is 0, x is 1
So now new limit are 5 and 1
Now to main thing!
First thing I do is find the dy/dx of substitution.
not of this >> x = t^2 + 1
make t the subject first.
t^2 = x - 1
t = (x - 1)^1/2 [power 1/2 is square root]
okay now, take dy/dx, but to be precise dt/dx
dt/dx = 1/2 ( x - 1)^(-1/2)
Now next thing!
We now should substitute the t's of formula.
since x=t^2 +1
then this
4t^3 ln(t^2 + 1)
is
4t^3 lnx
One more t is left! what is t alone?
x = t^2 +1
t = (x - 1)^1/2
so sub this and get
4((x-1)^1/2)^3 lnx
4(x-1)^3/2 ln x
Now add the differential to the top equation
4(x-1)^3/2 ln x 1/2 ( x - 1)^(-1/2)
4/2 (x-1) ^(3/2 -1/2) lnx
2 (x-1) ^1 ln x
2x - 2 ln x , with limits 5 to 1
It depends on you actually.PhyZac .. do u think M2 is easier or S1 ?
PhyZac .. do u think M2 is easier or S1 ?
and for me M2 is the best as i was never good at statisticsPhyZac .. do u think M2 is easier or S1 ?
take something less than 90 degrees (1/2pi) because logically the angle looks smaller than 90 degrees i would say start with 1.5http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_32.pdf
PhyZac ; for no. 4 (ii) , what value should I take as x1 ?
I took pi, as x1.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_32.pdf
PhyZac ; for no. 4 (ii) , what value should I take as x1 ?
mechanics is always better than stats..stats EWWWWWWWWWWWWWWPhyZac .. do u think M2 is easier or S1 ?
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now