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nd ppl are asking now how to study? May Allah be with you people then!
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nd ppl are asking now how to study? May Allah be with you people then!
JazakAllah khair for this, it really helped.Check this, might help you, I too have problem, sorry.
You are lucky, i just finished this paper!Hii, can anyone solve this question in detail for me please?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_1.pdf Question 5, thanks,
Okay sure, but it will time.Physac dude, mind answering my question?
I will be immensely grateful...Okay sure, but it will time.
You dont have to do the first part. Just explain the last part, bro.Okay sure, but it will time.
thnku, thnku so much what grade to expect? are you giving A2 aswell?!You are lucky, i just finished this paper!
They said to find the distance between two points of intersection.
First we should find what are the points.
To do this we should do simultaneous equation.
3y= 4x+6 -----(1)
y^2 = 12x ----(2)
In equation (2)
x= y^2/12
Sub this to equation (1)
3y = 4(y^2/12) + 6
3y = y^2/3 +6
9y = y^2 + 18
y^2 - 9y +18 = 0
(y-3) or (y-6) = 0
y = 3 or y = 6
when y = 3 [sub to (1)]
3(3) = 4 x + 6
x = 3/4
so first point (3/4 , 3)
when y = 6
3(6) = 4x + 6
x = 3
so second point (3, 6)
Distance √(x1-x2)^2 + (y1-y2)^2
√(3-(3/4))^2 + (6-3)^2
= 3.75
Okay Alhamdulilah I finished. I really hope you gain help with this...took timeI will be immensely grateful...
Okay Alhamdulilah I finished. I really hope you gain help with this...took time
Aameeeeen, and you are welcome. More doubts do post but tomorrow i will solve. In Sha Allah.YOU MY FRIEND ARE A LIFE SAVER. MAY ALLAH BLESS YOU WITH LOTS AND LOTS OF MORE KNOWLEDGE.
THANK YOUUU!
i got an easier way !Hii, can anyone solve this question in detail for me please?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_1.pdf Question 5, thanks,
thnkuuui got an easier way !
first ANY case you find point of intersection .. EQUATE the two equations by making Y as the subject in both cases .....
so y = root of 12x----1
y=4x+6/3--------2
by equationg them you get two x values from a quadratics eqation ... plug this two x values in one of the equation and you get the y values! and then find the distance
Those points are when x = 0 and when y = 0http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_1.pdf
Question 9, part i, i did uptil finding the equation, but what about after that?! how did they find the points?
I will give you idea, if you still have doubt i will try to solve.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_1.pdf
Question 7, (i) how to do this? there are these types of questions in everryy paper!
i dunno the tan formula, can anyone explain?
and part (iii) what formula did they take for area of AOBT ?
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