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Mathematics: Post your doubts here!

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parti r= 1/(1/3tan x) hence r=3/tan(x)^2 it must be r must be less then 1 to be convergent hence
3/tan(x)^2 <1 hence tanx < under root 3 hence x< tan^-1 (under root of 3 ))
am i rite?
LoL I don't know what convergent means ! that's the problem :p
 
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duhh Multiplication and then how to equate them ? if you can please explain me how to find a and b please :D
alright man first of all you have to expand (1+ax)^6 using the binomial theorem ( i guess u have learnt that as it is part of ur syllabus) but not all of it like expand it up to the term x^3 onlyyy then expand (1-2x)^2 and multiply it with the answer u got when u did the binomial theorem..once u get an answer tell me..ok ? if u dont know how to use the binomial theorem then tell me also
 
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Guys, I have a question.
What is the most difficult P1 paper you have solved... ever? :p
 
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Guys, I have a question.
What is the most difficult P1 paper you have solved... ever? :p
haha u want the hardest paper everrrr? then try 2012 may june 22..damn i did that paper in may june and i had to take math again because of its difficulty
 
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haha u want the hardest paper everrrr? then try 2012 may june 22..damn i did that paper in may june and i had to take math again because of its difficulty

I did that, it was easy compared to november 11 p12. I couldn't even finish it, it exhausted me.
 
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hello,
i need help on Question no 1 of 9709/11/m/j/10 (may june 2010 paper 11)
Thank you
please do reply!
 
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Please Nov2012 v.13 no.6 i . no.7 ii , 8 iii ) , 9 all , 10 iii
11 ) ii and iv .. this paper is so hard for me :(
 
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alright man first of all you have to expand (1+ax)^6 using the binomial theorem ( i guess u have learnt that as it is part of ur syllabus) but not all of it like expand it up to the term x^3 onlyyy then expand (1-2x)^2 and multiply it with the answer u got when u did the binomial theorem..once u get an answer tell me..ok ? if u dont know how to use the binomial theorem then tell me also
Thanks man !! Got it ATLAST
 
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hello,
i need help on Question no 1 of 9709/11/m/j/10 (may june 2010 paper 11)
Thank you
please do reply!

you should know that tan (180-x) = -tan x .. (1)
and tan (90-x) = 1/ tanx .. (2)

i) if u used (1) --- > -k
ii) use ii --- >1/k
iii) by Pythagoras : tan = opp /adj thus tan = k/1 --> so hyp = ksquare+1square under square root
so sin =opp /hyp --> so k/= ksquare+1square under square root .
 
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integrate dy/dx than put the values of x and y given in question to find C nd than thats ur equation
 
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