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i didn't get it :/aww man this is a pretty weird question.. took me so much time to solve it
well umm you found that 30 and 150 degrees in the first part right, so they say that" theta" here in [n(theta) = ?] is 10 so you plug in theta=10 and the smallest angle was 30
so umm 10n = 30 since 30 was the smallest angle therefore n=3
then umm n(theta) = 720 + 150 (since they ask for the largest solution) put n =3
3(theta)= 870
theta =290
ok well put it this way they say that the smallest possible value of theta in n(theta) is 10 and since the smallest angle was 30, n(theta)=30,i didn't get it :/
I mean can u walk me through ur thinking process tooo.... i mean the solution of this equation means the value of Sin(theta) right??
urgghhh i'm not grasping this one.... can u plz explain :O _-_
well this is the thinking on which value is sin curve the minimum it is minimum at 30 degrees acording to first part hencei didn't get it :/
I mean can u walk me through ur thinking process tooo.... i mean the solution of this equation means the value of Sin(theta) right??
urgghhh i'm not grasping this one.... can u plz explain :O _-_
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf
Question- 6(ii), 7(iii), 11(ii) please..
Thank you..
for 6ii take the determinent = 0http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf
Question- 6(ii), 7(iii), 11(ii) please..
Thank you..
for 11iihttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf
Question- 6(ii), 7(iii), 11(ii) please..
Thank you..
for 11ii
take the area under line graph.... it will give u all the area under graph shaded + unshaded
take area under curve by integrating the curve equation (gives unshaded are)
subtract the two
no i know the formulae i know the limits
but my answer is comming wrong idk y ?
yeah but in (ii) It's asking about a different equation , not the one i already sketched. and it's for one mark , do i have to sketch that as well?For the first part you HAVE to sketch .. The. State the number of solutions .. Let's say 2
So then you check the other question it says upto 20pie but u have till 0-2pie .. So u consider o-2pie as one revolution and then count number of revolutions u need .. Till 20 pie it will be around 10 maybe .. And u have for one resolution 2 solutions so for 10 resolutions .. Just multiply
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