canu answer my wuestion :/thnakkks
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canu answer my wuestion :/thnakkks
Prove the identity (sin x + cos x)(1 − sin x cos x) ≡ sin3 x + cos3 x. [3]
(ii) Solve the equation (sin x + cos x)(1 − sin x cos x) = 9 sin3 x for 0◦ ≤ x ≤ 360◦. can anyone solve part (ii) i dont get it @A
I tried my best to understand, but it is hard. I found this.
https://www.xtremepapers.com/commun...st-your-doubts-here.9599/page-323#post-485476
answer is 26.6Take sin3x + cos3x as (sinx + cosx)(1 - sinx cosx)
So you get...
sin3x + cos3x = 9sin3x
Divide both sides by sin3x
1 + cos3x/sin3x = 9
1 + tan3x = 9
tan 3x = 8
3x = tan^-1(8)
x= 27.6 <=== Is this correct?
is it p1?Prove the identity (sin x + cos x)(1 − sin x cos x) ≡ sin3 x + cos3 x. [3]
(ii) Solve the equation (sin x + cos x)(1 − sin x cos x) = 9 sin3 x for 0◦ ≤ x ≤ 360◦. can anyone solve part (ii) i dont get it @A
lol chutia me i have solved this on my own now thanks anywaysTake sin3x + cos3x as (sinx + cosx)(1 - sinx cosx)
So you get...
sin3x + cos3x = 9sin3x
Divide both sides by sin3x
1 + cos3x/sin3x = 9
1 + tan3x = 9
tan 3x = 8
3x = tan^-1(8)
x= 27.6 <=== Is this correct?
yea p1 dudeis it p1?
am also gettting 26.6. what year did u take it from?yea p1 dude
Guys . tommorow we al have P1 . So i was thiinking why dont we share some tips that hepl us in solving papers . Let me the first to initiate :
- colinear of parallell vectors have a ratio of k . EG if a and b are colinear then a^/b^ =k .
Guys . tommorow we al have P1 . So i was thiinking why dont we share some tips that hepl us in solving papers . Let me the first to initiate :
- colinear of parallell vectors have a ratio of k . EG if a and b are colinear then a^/b^ =k .
Haha.. Me tooI didn't get it.
are they correct..
haha . Look if two vectors are collinear of parallel then they have a common ratio between them . suppose a=(2.4.6) and b=(1.2.3)
a/b =2 and so they are both collinear
You are welcome, I am glad I did something to help you!!Thank you Thank you Thank you!
I got it.
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