Mathematics: Post your doubts here!

[A star]

i hope u guys get it now bcz had a hard time making that number line -_-
syed1995 and PANDA- but if u don't just ask again and i'll c wat i can do

dnt mind but one word for no line KHUWARI xD .

 

[Just visiting]

Ummm....I need your help guys in solving Q7 last part (iii)
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w10_qp_12.pdf
here's a quick picture
Thanks in Advance

 

[PANDA-]

i hope u guys get it now bcz had a hard time making that number line -_-
syed1995 and PANDA- but if u don't just ask again and i'll c wat i can do

Sorry... I don't get it LOL.

 

[daredevil]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_12.pdf
Question- 10 (a)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_12.pdf
Question- 3(a)
Please.. Thank You

hey
for Q 10a : -
u know from the given data that S6 = 360 because the total angle in a circle is 360
and they are in arithematic progresion which means the first angle is the smallest and they go on increasing so the smallest angle will b the first value i.e. a
largest angle = 4a

use the formula S6 = n(a+l)/2

where a is the first value
S6 is the sum of 6 values
l is the last term

hope u will be able to solve it now becauase after u get a then u just add radii to the arc length

 

[Rutzaba]

i hope u guys get it now bcz had a hard time making that number line -_-
syed1995 and PANDA- but if u don't just ask again and i'll c wat i can do

chek inbox

 

[daredevil]

Sorry... I don't get it LOL.

urggh well that's alll i can do.... last day pe can't teach u the no line i'm afraid sorry

 

[daredevil]

A star yeah i know and the wors tpart is they didn't even get it
ah well

 

[A star]

too bad

 

[Maz]

I think this will help:

• If (b^2-4ac) > 0 , the equation will have 2 roots.
• If (b^2-4ac) < 0 , the equation will have no roots.
• If (b^2-4ac) = 0 , the equation will have 1 root.

 

[Rutzaba]

I think this will help:

• If (b^2-4ac) > 0 , the equation will have 2 roots.
• If (b^2-4ac) < 0 , the equation will have no roots.
• If (b^2-4ac) = 0 , the equation will have 1 root.

graph hunz ... they need graph

 

[Maz]

graph hunz ... they need graph

Graphs for what?

 

[Rutzaba]

Graphs for what?

never mind

 

[Maz]

never mind

huh??? now i'm confused.

 

[Maz]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf

There's a problem in 6(i) right?

 

[Rutzaba]

Guys tell me wat u dun get? panda @syed1996
U kno 2 values of k but dunno wat in equality to put ryt?

 

[Magenta]

Somebody please do this!
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_11.pdf
Q7 b)

 

[Maz]

Somebody please do this!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_11.pdf
Q7 b)

You should remember that |r| < 1 for a convergant sequence
In this question r = 1/3 tan^2 θ
therefore, 1/3 tan^2 θ < 1
tan^2 θ < 3
tan θ < [sqrt]3
θ < π/3

 

[doctorofelectronics]

kx^2+1=kx
kx^2-kx+1=0 for this b^2-4ac must be less than zero (<0)
(-k^2)-(4*k*1)<0
k^2-4k<0
k(k-4)<0
so k can be 0 or 4
since the coefficient of k^2 is positive the graph should be a parabola.
The answer is 0<k<4
Please check the graph
The graph is of y=k(k-4)
since we want k(k-4)<0
we want y<0 in our graph
Sorry for the bad drawing. Hope it helps

 

[ZainH]

If f(x)=x²-4x+7 for x>2 and g(x)= x-2 for x>2

The function h is such that f=hg and the domain of h is x>0
Q. Obtain an expression for h(x) .

 

[doctorofelectronics]

Here is the graph