Mathematics: Post your doubts here!

[salvatore]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w10_qp_61.pdf
Could someone please explain qn no. 6 (iii, iv & v)? I don't understand what to do..
Thanks

 

[Pie-man]

we had this

This question rings a bell, which year ?
btw I think time should be t-2.

argument yesterday and it still is confusing why P has the t+2 instead of the Q

 

[Pie-man]

less than than 17 hours left for mechanics

 

[Esme]

less than than 17 hours left for mechanics

Are you worried ?

 

[Pie-man]

yeah cause i screwed up bad with pure and really hope mechanics gets me the A .... so no not at all

 

[Esme]

we had this
argument yesterday and it still is confusing why P has the t+2 instead of the Q

Well maybe you can get it if you imagine it happening in your head...

 

[haha101]

less than than 17 hours left for mechanics

Keep calm n hope no hard Q comes for M1

 

[Esme]

yeah cause i screwed up bad with pure and really hope mechanics gets me the A .... so no not at all

Oh! Well then I hope it goes well for you even though it has a lower weightage than P1..

 

[Esme]

Keep calm n hope no hard Q comes for M1

Haha insha'Allah

 

[Pie-man]

Keep calm n hope no hard Q comes for M1

yeah no hard questions at all

 

[Pie-man]

Oh! Well then I hope it goes well for you even though it has a lower weightage than P1..

thank you and btw i didn't screw it soo bad .. just screwed it so there might still be hope

 

[ZainH]

Ohlord, I can't think atm
Can someone solve these 2 simultaneous equations for me.

5.5sinx = wgcosx
And
5.5cosx + wgsinx = 7.3

 

[D0cEngi]

Plz help me with question 7 of this ppr. Plz Plz Plz.
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_41.pdf

 

[mominzahid]

It's given you the maximum velocity, at max velocity acceleration is 0.

So, since we have the equation for velocity , we need to change it to acceleration by differentiating it.
This gives us , 12ot-3t^2
We take this as 0 and find the value of t

120t-3t^2 = 0
3t(40t-4) = 0
t= 40

Now that we have a value of t , replace it in the original equation for velocity and take velocity as 6.4 since thats it's max.
k(60t^2-t^3) = 6.4
k(32000) = 6.4
k= 6.4/32000
k= 0.0002

Hope you get it x)


You're welcome.

Got Itt...
Thanks ..
Can u please explain q3? same paper..

 

[Pie-man]

Well maybe you can get it if you imagine it happening in your head...

WOW....that sounded deep

 

[haha101]

Yeah

 

[Pie-man]

Plz help me with question 7 of this ppr. Plz Plz Plz.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_41.pdf

here is the whole idea (or how i did it) just draw a vertical line at point B to get a letter Z, and by using trigonometry get the angles so you can make a resolution, then Tension c and Tension a will be equal to each other (with the sine and cosine of course) and 8 would be equal both added together.

then get the tensions by substitution between both equations.

 

[haha101]

here is the whole idea (or how i did it) just draw a vertical line at point B to get a letter Z, and by using trigonometry get the angles so you can make a resolution, then Tension c and Tension a will be equal to each other (with the sine and cosine of course) and 8 would be equal both added together.

then get the tensions by substitution between both equations.

man i cant understand a thing Please any diagram or something

 

[GorgeousEyes]

Please juun012 v.42 no.5 with steps pleaase .

 

[ZainH]

Got Itt...
Thanks ..
Can u please explain q3? same paper..

Oh that's easy just make 2 simultaneous equations.
Use s=ut+1/2at^2

So your first equation is: 55=5u+12.5a
And second one is: 120=10u+50a

Solve them simultaneously, you should get a=0.4 and u=10 m.s-1