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I found this.http://ncalculators.com/math-worksheets/how-to-calculate-class-interval-arithmetic-mean.htm
errrrrrr........
errrrrrr........
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ok i'm pretty sure i did this question for my mocks prep but i am totall null blank ryt now :O if anyone answers then tag me too .... it just isnt hitting me -_-daredevil ,i have a doubt
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_6.pdf , in the markscheme (http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_6.pdf) where did they get 0.674 for question 1?
so they havent made class boudaries here?! :OI found this.http://ncalculators.com/math-worksheets/how-to-calculate-class-interval-arithmetic-mean.htm
errrrrrr........
ln(x²) is not the same as [ln(x)]². Try again using the latter!http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_32.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_ms_32.pdf
Q9 ii) I can't seem to get the answer, even though I think I'm integrating it right.
We have to integrate x lnx^2
I'm doing it by integration by parts but I don't get the answer as in the marking scheme..
Anyone? Please show me the workings
applepie1996
i)http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_6.pdf
Question 6, i and ii, how to get the answer?
thnksss!i)
First round: 32 teams, 16 winners, 16 losers
These 16 losers play only one game as they are knocked out in the first round.
ii)
Second round: 16 teams, 8 winners, 8 losers
The 8 losers in this round play exactly two games. They qualify for the second round after winning in the first but then get defeated!
(i)
So P(X=0) means when no blue is taken,
it will be
7/1o x 6/9 x 5/8 x 4/7 = 1/6
first 7 orange from 10 total, then 6 from 9 total (because one is taken) etc..
P(X=1)
(7x6x5x3) / (10x9x8x7) x 4 = 1/2
we will take 3 from orange so first 7 then 6 then 5 left, for blue we take once so only 3
down is total number, that is, 10 then 9 , 8 ,7
x4 because blue can be taken first second third or fourth
(ii)
for 0 we know 1/6
for 1 we know 1/2
for 2 it will be 4C2 x (3x2x7x6) / (10x9x8x7) = 3/10 [i take 4 combine 2 to get how many ways can we get 2 blues]
for 3 it will be 4C3 x (3x2x1x7) / (10x9x8x7) = 1/30
X=x..... || 0 || 1 || 2 |||| 3 |
P(X=x) |1/6|1/2|3/10| 1/30|
daredevil ,i have a doubt
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_6.pdf , in the markscheme (http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_6.pdf) where did they get 0.674 for question 1?
Did you get it? or u still need some help?! let me know, I'll explain you thenCan someone please explain how question 8(full) is solved? Which steps must be included etc.
This paper
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_6.pdf
Question 6, i and ii, how to get the answer?
I've watched the video. It still doesn't make sense. If you take the class boundaries as 0 and 9.5, you'll get the midpoint as 4.75, whereas the mark scheme clearly states it as 4.5. That's what I don't understand!!!!!!!!!!!!!!!!!!!!!!!!!
Well, May Allah S.W.T help you with this thing! Aameen.I found this.http://ncalculators.com/math-worksheets/how-to-calculate-class-interval-arithmetic-mean.htm
errrrrrr........
oooh thanks... i was thinking about subtracting some but lost my bearings so couldn't wrap my head around wat to subtract even though it was pretty clear... thanks a bunchdaredevil
They told us that 225 out of the 900 cartons has more than 1002 milliliters. So what is the probability that a carton has more than 1002 milliliters? It's 225/900= 0.25. So if we were to standardize 1002 milliliters, you'd get a z value that would correspond to a probability of 0,25 in the normal distribution table. But you don't have 0.25 in the table, so you (1-0.25 = 0.75). So the probability that you would be looking for in the table is 0.75. Which is 0.674. Since the probability is GREATER than 1002, the sign won't change in this case.
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