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Mathematics: Post your doubts here!

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Hello everybody.
I'm having a bit of a problem in mechanics, Resolving Forces to be precise. If someone can post notes on Resolving Forces it'll be really helpful. Thanks :D
 
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the cubic root of 2 + the cubic root of 16
Thats my doubt. Plz help. thks


I am not writing 3 in front of √ but here √ means 3√ (Cube Root of)
√2 + √16
√2 + √(2*2*2*2) 16 can also be represented as 2^4..
√2 +√[(2^3)*2]
now taking the cube root of 2^3 will give you 2.. so 2 will come out of the root sign.
√2 + 2√2
3 √2

so final answer will be 3* (Cube root of 2)

Hope that helps.. also resolve the big numbers into the power of their standard form (TAKING LCM to find the power of standard form is very helpful in this) and it shouldn't seem too hard with practice.

If you have any more questions.. just don't hesitate to tag me..

Cheers
 
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Can you pls help out with that question? :)
 

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can you help me with these questions :
1) Find all values of k if the equation x^2 + (k-2)x + 10-k = 0 has equal roots.
2)The equation x^2 - 2x + 1 = p(x-3) has equal roots. Find the possible values of p.
 
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Can you pls help out with that question? :)


OD is (4i+4J+5k)

Firstly to get to O to D you need to go 5 steps UPWARDS (and it says top is 5m above base) So K = 5

Then DE = 6 and OA =14 so the difference is 8 there. so the two bits at the side are 4 each. (4 + 8 + 4 = 16)
So we need to move in the "i" direction 4 steps. i = 4

Finally note that D is not directly under O so you have to move half the length of OC to get under it. 8/2 =4. So 4J

(4,4,5)

Mag is square root of (4^2 + 4^2 + 5^2) = Square root of 57

Try OB now.
 
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can you help me with these questions :
1) Find all values of k if the equation x^2 + (k-2)x + 10-k = 0 has equal roots.
2)The equation x^2 - 2x + 1 = p(x-3) has equal roots. Find the possible values of p.


Just use the discriminant. b^2-4ac = " "

"=0" if one root or equal roots
"<0" if no roots
">0" for two roots
 
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i really need help for may/june 2013 no 6 paper 12


625523_10202100744463875_634667839_n.jpg
 
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i really need help for may/june 2013 no 6 paper 12


Ok. So we have
OA (1i, -2j, 2k) and OB (3i, pJ, qK)

for i) It says both are parallel. The clue is the "i" in both vectors. It goes from 1 to 3. Therefore "x3" OA to get to OB.

So
-2 x "3" = -6 = p
2 x "3" = 6 = q

for ii) it says 90 degrees which means the dot product =0
(1,-2, 2) and (3, p, 2p)
so:
(1 x 3) + (-2 x p) + (2 x 2p) = o
3 - 2p + 4p = 0
2p = -3
p=-3/2

finally iii)

AB means b-a (for e.g CB means b-c, AD means d-a etc etc)
so: (3, 1, 8) - (1, -2, 2) = (2, 3, 6)

To get the Unit vector first find the Magnitude of it which is Square root of (2^2 + 3^2 + 6^2)
Which is square root of 49 ==> 7

Lastly you gotta divide vector by this number.
Hope you understood!
 
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