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Mathematics: Post your doubts here!

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solve these questions
inequality (x+1)/(x-1) <4
find stationary point y=2x^2 + e^-x^4 .....y=x^n-lnx^n for n>= 1
solve the integration of 1/2x dx
plz explain

(x+1) < 4(x-1) ==> x+1 < 4x - 4 ==> +1 + 4 < 4x -x ==> 5< 3x so x > 5/3

dy/dx = 4x - e^-x WAit what? :s e^-x^4? da fuq is this? :s

1/2x dx ==> ~ is integration sign for example..

~ 1/2x dx ==> differentiation of 2x is 2.. so numerator should be 2..
1/2 ~ 2/2x dx

1/2 ln 2x + c
 
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(x+1) < 4(x-1) ==> x+1 < 4x - 4 ==> +1 + 4 < 4x -x ==> 5< 3x so x > 5/3

dy/dx = 4x - e^-x WAit what? :s e^-x^4? da fuq is this? :s

1/2x dx ==> ~ is integration sign for example..

~ 1/2x dx ==> differentiation of 2x is 2.. so numerator should be 2..
1/2 ~ 2/2x dx

1/2 ln 2x + c
power of e is -x raise to power 4.......plz explain this question and the integration
 
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power of e is -x raise to power 4.......plz explain this question and the integration

what kind of question is that o_O
anyways.. it be like

- 4x^3 x e^-x^4 will differentiation of that thing and equate the whole differentiation to dy/dx = 0 and you will get staionary poitn
 
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Need help with this asap, pls! Anyone?:)
Solve the equation 3^x+2 = 3^x + 3^2 , giving your answer correct to 3 significant figures.
 
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Anyone appearing for P62 this time!???? I am bit worried, since i donot do well in statistics! Any suggestions for me?
 
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its 3^(x+2). Your former guess. :)
see
3^(x+2) = 3^x + 3^2
by log property u can replace powers as coefficients such that if
a^b then it can convert to b lna
so this will become...
(x+2) ln 3 = x ln3 + 2 ln3
we also know that if two ln functions are adding they will multiply
such that lna + lnb = ln (ab)
so we get
(x+2) ln3 = (2x) (ln3)
remove ln3 on both sides
2x= x+2
x=2
Hope thats the correct answer...
 

KZW

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9707/61/O/N/11 Qn 5 .. Pl help.

I'm going to assume you meant 9709 for Math.

Anyway, draw out the normal distribution graph, with lines showing
- 20(the mean) in the middle
- 12 either side of the mean, specified in the question (8 and 32)

The area in between, P(8<X<32) is 94%. So far so good?
So now you'll want to find P(X<32). Since its symmetrical, (look at the normal graph that you drew). P(X<32) = 0.5(1 - 0.94) + 0.94 = 0.97 (97%).

Convert 0.97 to its Z value, which is 1.881.
Since Z= (x-u)/sd , we can equate 1.881= (32-20)/sd

Rearrange and it should give sd=6.38

I hope that helped, good luck for the stats paper tomorrow!
 
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1 It is known that, on average, 2 people in 5 in a certain country are overweight. A random sample of
400 people is chosen. Using a suitable approximation, find the probability that fewer than 165 people
in the sample are overweight.
A box contains 300 discs of different colours. There are 100 pink discs, 100 blue discs and 100 orange
discs. The discs of each colour are numbered from 0 to 99. Five discs are selected at random, one at
a time, with replacement. Find
(i) the probability that no orange discs are selected, [1]
(ii) the probability that exactly 2 discs with numbers ending in a 6 are selected, [3]
(iii) the probability that exactly 2 orange discs with numbers ending in a 6 are selected, [2]
(iv) the mean and variance of the number of pink discs selected.

please help me with these questions
 
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