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Mathematics: Post your doubts here!

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5(i)
From what i have learned. for |z-i|=2 draw circle with center at 0,i. z is at o,o and -i means that now center point is 0,i if it was +i then center point would be 0,-i just opposite. Same for real numbers i.e |z-1| would mean starting point is 0,1. Now the 2 is radius. SO |z-i|=2 means draw circle with radius 2 and center 0,i. modulus of imaginary number is a circle.
Thanks a lot
umm.. what about part ii?
 
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Please someone solve Q8b, just how to find the least value for z-w with explanations of why you are doing each step pleasee!
 

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Hi guys,i got a problem here.Need help.A question no 10(b part 2).Thanks a lot.....
 

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Thanks a lot
umm.. what about part ii?
9709_s08_qp_3.pdf can someone solve Q5 please
Sorry I was feeling bored to solve part ii that time haha.
OK now,
substituting value of z and simplifying you get. 1 /(2cosθ+2)-2sinθ i
Multiplying by it's conjugate i.e. (2cosθ +2)+2sinθ i and again simplifying we get,
(2cosθ +2+2sinθ i) / 4cos^2θ + 8cosθ + 4 + 4sin^2θ
=numerator/ 8+8cosθ [4cos^2θ + 4sin^2θ = 4]
Now separating the real part only from numerator 2(cosθ +1) / 8(cosθ +1)
Hence real part = 1/4
 
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Hi guys,i got a problem here.Need help.A question no 10(b part 2).Thanks a lot.....
Can you give me the values of p,q,alpha and beta?
EDIT: OK I have solved it and I am going to attach the files hope you understand.
 

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Yes please someone explain this question with explanations for every step. I know how to do the diagram, im just having trouble finding the least value for z-w.
can you show me the diagram? I think we should find least value of |Z|-|W|
 
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