Mathematics: Post your doubts here!

[Saad Mughal]

View attachment 41648

Help with (iii) plz...???

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There are two ways to do this, either equate the equation you found in part (i) to 0 (since displacement is 0 at O).
Or, use a definite integral with limit t (at O) and 0 (at point where object is at rest) and equate it to 36, since the displacement till O covered is 36.

 

[A star]

My answer is wrong what's the point of explaining

i mean the method you did it was beyond me what you did sorry for not being helpfull tbh my mind is right now filled with m1+chem so dont ask :3

 

[itallion stallion]

i mean the method you did it was beyond me what you did sorry for not being helpfull tbh my mind is right now filled with m1+chem so dont ask :3

Hahah.okay no problem!

 

[Saad Mughal]

View attachment 41651 HELP

(i) The body is in equilibrium, there are three force acting downwards and two forces acting upwards. According to the conditions for equilibrium.
Sum of upward forces = Sum of downward forces.
Q + R = 120g.
Taking moments about Q,
(60+20)(0.8)(g) = (0.4)(40)(g) + (1.6)(R)
1.6R =48g
R = 30g
Therefore, Q = 120g - 30g = 90g.

Reaction at Q = 90(10) = 900 N.
Reaction ap R = 30(10) = 300 N.

(ii) Reaction at Q = 2 * Reaction at R.
Hence, Q + R = 120g
3R = 120g
R = 40g

Taking moments about Q,
Let x be the distance from Q to x.
The body is in equilibrium, therefore Arthur has to sit in between Q and R. Hence,
60g(x) + 20g(0.8) = 40g(0.4) + 40g(1.6)
60g(x) = 64g
x = 16/15 = 1.07 m.

 

[Thought blocker]

(i) The body is in equilibrium, there are three force acting downwards and two forces acting upwards. According to the conditions for equilibrium.
Sum of upward forces = Sum of downward forces.
Q + R = 120g.
Taking moments about Q,
(60+20)(0.8)(g) = (0.4)(40)(g) + (1.6)(R)
1.6R =48g
R = 30g
Therefore, Q = 120g - 30g = 90g.

Reaction at Q = 90(10) = 900 N.
Reaction ap R = 30(10) = 300 N.

(ii) Reaction at Q = 2 * Reaction at R.
Hence, Q + R = 120g
3R = 120g
R = 40g

Taking moments about Q,
Let x be the distance from Q to x.
The body is in equilibrium, therefore Arthur has to sit in between Q and R. Hence,
60g(x) + 20g(0.8) = 40g(0.4) + 40g(1.6)
60g(x) = 64g
x = 16/15 = 1.07 m.

ty

 

[Namehere]

(i) The body is in equilibrium, there are three force acting downwards and two forces acting upwards. According to the conditions for equilibrium.
Sum of upward forces = Sum of downward forces.
Q + R = 120g.
Taking moments about Q,
(60+20)(0.8)(g) = (0.4)(40)(g) + (1.6)(R)
1.6R =48g
R = 30g
Therefore, Q = 120g - 30g = 90g.

Reaction at Q = 90(10) = 900 N.
Reaction ap R = 30(10) = 300 N.

(ii) Reaction at Q = 2 * Reaction at R.
Hence, Q + R = 120g
3R = 120g
R = 40g

Taking moments about Q,
Let x be the distance from Q to x.
The body is in equilibrium, therefore Arthur has to sit in between Q and R. Hence,
60g(x) + 20g(0.8) = 40g(0.4) + 40g(1.6)
60g(x) = 64g
x = 16/15 = 1.07 m.

Is this M1 or M2?

 

[Saad Mughal]

Is this M1 or M2?

M1.

 

[Thought blocker]

M1.

Is this M1 or M2?

Suchal Riaz ?

 

[A star]

M1.

which year is this O.O havent seen it uptill now. thought it was M2

 

[Saad Mughal]

which year is this O.O havent seen it uptill now. thought it was M2

No idea. Ask Thought blocker.

 

[Thought blocker]

No idea. Ask Thought blocker.

Random question

 

[salvatore]

Here u go!

Thank you so much

 

[AnujaK]

Hi everyone
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Please do check it out!
https://sites.google.com/site/fromatoscom/home

 

[Suchal Riaz]

M1.

according to CIE syllabus this is in M2 not in M1

 

[Saad Mughal]

according to CIE syllabus this is in M2 not in M1

Moments? I googled it after A star asked me and it is M1, Edexcel. Haven't gone through the CIE M1 syllabus so don't know.

 

[Suchal Riaz]

Moments? I googled it after A star asked me and it is M1, Edexcel. Haven't gone through the CIE M1 syllabus so don't know.

So are you doing Edexcel or CIE? I clearly mentioned in my post that it is not part of 'CIE syllabus'. Thought blocker, who asked the question, is doing CIE board.

 

[Saad Mughal]

So are you doing Edexcel or CIE? I clearly mentioned in my post that it is not part of 'CIE syllabus'. Thought blocker, who asked the question, is doing CIE board.

I never said it was in the CIE syllabus either. I clearly stated I have no idea which year the question is from because a fellow member asked it, I googled after that and found it to be M1 Edexcel and so I said so.

 

[Suchal Riaz]

I never said it was in the CIE syllabus either. I clearly stated I have no idea which year the question is from because a fellow member asked it, I googled after that and found it to be M1 Edexcel and so I said so.

I was just asking which board you are taking.

 

[Saad Mughal]

I was just asking which board you are taking.

You know which board I'm taking.

 

[Suchal Riaz]

You know which board I'm taking.

sindh board