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You know which board I'm taking.I was just asking which board you are taking.![]()
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You know which board I'm taking.I was just asking which board you are taking.![]()
sindh boardYou know which board I'm taking.![]()
sindh board![]()
This should workhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_42.pdf
Q7 part 1
Could someone please show the correct sketch of the graph?![]()
How do u write such thrillers?Conclusion... dont look hee and there while doing maths xD
acceleration=v-u / t; so t=(v-u)/aplease![]()
There is no change in height, the load is being pulled on a straight horizontal path.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_43.pdf
Q2 i.... Isn't the formula supposed to WD by P = Gain in Ke+ Gain in Pe + Work Done against resistance.
Why they didn't use Gain in PE.
ideas from googles lolHow do u write such thrillers?
you just have to sktch the diagram with important coordinates indicated with a roughly relationship between them but box and whisker plot and frequency diagrams and histograms should properly indicated.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_ms_43.pdf
Q5 (iii)
Am i supposed to draw a neat diagram, everything scales, on a graph or just a kind of rough diagram, with those time and velocity labels without any scale?
Are all the graphs supposed to drawed the same way?
Integration
acceleration=v-u / t; so t=(v-u)/a
time for P to reach maximum height = 17-0 / 10 = 1.7 s
time for P to return to ground = 2*1.7=3.4 s
time for Q to reach maximum height = 7/10=0.7
time for Q to return = 1.4s
the difference in time is adjusted by throwing Q Ts later. so T=3.4-1.4=2s
this guy writes too u knowIntegrationIntegrate acceleration and it becomes velocity. As it starts from rest we know the constant is zero. Equate velocity to 90 and you will get the time
I used v=u+atIntegrationIntegrate acceleration and it becomes velocity. As it starts from rest we know the constant is zero. Equate velocity to 90 and you will get the time
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